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lozanna [386]
3 years ago
9

What are the similarities and differences between buoyancy and thrust?

Physics
1 answer:
padilas [110]3 years ago
6 0

Answer:

Buoyancy - it is what perceive as the tendency of an object to rise when when it is submerged in a fluid it is can be defined as the ability of an object to float in the fluid .

Thrust - It is a reaction forced described quantitavely by newton third law

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A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder?
AlekseyPX

Answer: 4m/s

Explanation:

8 0
3 years ago
When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and identify which of the foll
goldenfox [79]

Answer:

a) false b) true c) true d) false and e) true

Explanation:

a) false.   All the energy applied is used for the phase change, so the temperature remains constant.

b)   true.   The kinetic energy is associated with the speed of the particles and they have more mobility in the liquid, therefore, more kinetic energy.

c)   true.   Since energy is used for state change

d)  false.   In general, mobility and temperature are proportional

e)  true.  Heat is the source of energy for the change of state

4 0
3 years ago
Read 2 more answers
Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for wiring receptacles. Such ci
Alecsey [184]

Given Information:  

Current = I = 20 A

Diameter = d = 0.205 cm = 0.00205 m

Length of wire = L = 1 m

Required Information:  

Energy produced = P = ?

Answer:  

P = 2.03 J/s

Explanation:  

We know that power required in a wire is

P = I²R

and R = ρL/A

Where ρ is the resistivity of the copper wire 1.68x10⁻⁸ Ω.m

L is the length of the wire and A is the area of the cross-section and is given by

A = πr²

A = π(d/2)²

A = π(0.00205/2)²

A = 3.3x10⁻⁶ m²

R = ρL/A

R = 1.68x10⁻⁸*(1)/3.3x10⁻⁶

R = 5.09x10⁻³ Ω

P = I²R

P = (20)²*5.09x10⁻³

P = 2.03 Watts or P = 2.03 J/s

Therefore, 2.03 J/s of energy is produced in 1.00 m of 12-gauge copper wire carrying a current of 20 A

8 0
3 years ago
A sinusoidal transverse wave of amplitude ym = 8.4 cm and wavelength = 5.3 cm travels on a stretched cord. Find the ratio of the
Scilla [17]

Answer:

The ratio is 9.95

Solution:

As per the question:

Amplitude, y_{m} = 8.4\ cm

Wavelength, \lambda = 5.3\ cm

Now,

To calculate the ratio of the maximum particle speed to the speed of the wave:

For the maximum speed of the particle:

v_{m} = y_{m}\times \omega

where

\omega = 2\pi f = angular speed of the particle

Thus

v_{m} = 2\pi fy_{m}

Now,

The wave speed is given by:

v = f\lambda

Now,

The ratio is given by:

\frac{v_{m}}{v} = \frac{2\pi fy_{m}}{f\lambda}

\frac{v_{m}}{v} = \frac{2\pi \times 8.4}{5.3} = 9.95

8 0
3 years ago
In a low-density cloud, the internal pressure is much too low to support the weight, so the cloud must __________, eventually pr
andrey2020 [161]

The answer to this question is flatten

so the cloud must <u>flatten</u> eventually producing the galaxy s disk.

3 0
3 years ago
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