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Citrus2011 [14]
3 years ago
15

What service is provided for HIV testing and what’s the important of this service?

Physics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

HIV Testing Services is an entry point to HIV prevention, treatment, care and support. It is expected that when people know their HIV status they will make informed choice on HIV prevention or if positive, access other services. Testing yourself for HIV is important for your health, your relationships, your life and your future. The growth of new infections continues to pose serious health risks. ... The fact is that HIV is preventable, and you can reduce or eliminate your risk. And early detection can lead to early treatment and better outcomes.

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g A 2.3 kg block is attached to the spring, and it is released from rest 0.7 m from the spring's equilibrium position. Neglectin
DedPeter [7]

Answer:

3.71 m/s

Explanation:

From the law of conservation of linear momentum, since we are neglecting minor energy losses due to friction then we can express it as mgh=0.5mv^{2} since all the potential energy is transformed to kinetic energy

Making v the subject of the formula then v=\sqrt {2gh} and here m is the mass of the block, g is acceleration due to gravity, h is the height. Substituting 0.7 m for h and 9.81 for g then we obtain that v=\sqrt {2\times 9.81\times 0.7}=3.705941176 m/s\approx 3.71 m/s

6 0
3 years ago
A friend tells you that a rowboat is propelled forward by the force of its oars against the water. First explain whether the sta
stellarik [79]
It is correct, the action is paddling, where you move the water backwards, and the reaction is the boat moving forwards.
7 0
3 years ago
A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00°C, the resistance of the carbon r
dusya [7]

Answer:

28 degree C

Explanation:

We are given that

T_1=4.00^{\circ}

R_1=217.7 \Ohm

R_2=215.1\Ohm

\alpha=-5.00\times 10^{-4}C^{-1}

We have to find the temperature on a spring day when resistance is 215.1 ohm.

We know that

\alpha(T_2-T_1)=\frac{R_2}{R_2}-1

Using the formula

-5.00\times 10^{-4}(T_2-4)=\frac{215.1}{217.7}-1

-5\times 10^{-4}(T_2-4)=0.988-1=-0.012

T_2-4=\frac{0.012}{5\times 10^{-4}}=24

T_2=24+4=28^{\circ}C

Hence, the temperature  on a spring day 28 degree C.

7 0
3 years ago
Which one does not affect the gravitational force between the 1 point
Zinaida [17]

Answer:

D. The net electrical charge of the Earth.

Explanation:

All the other three choices affect the gravitational force. I remember from middle school.

6 0
3 years ago
A 92.6 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large piece of chocolate cake rated at 735 (
Kitty [74]

Answer:

349 m

Explanation:

Parameters given:

Mass of climber, m = 92.6 kg

Amount of food calories = 735

1 food calorie = 103 calories

735 food calories = 75705 calories

1 joule is equal to 0.239 calories. Therefore, 75705 calories will be 316749.72 joules.

Hence, this is the amount of work the climber must do work off the food he ate.

Work done is given as:

W = Force * distance

W = m * g * h

h = W/(m * g)

h = 316749.72/(92.6 * 9.8)

h = 349 m

4 0
3 years ago
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