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Ahat [919]
4 years ago
9

What role does the somatic nervous system play?

Physics
1 answer:
kodGreya [7K]4 years ago
4 0

Explanation:

The somatic nervous system coordinates the voluntary control of movement in the body system.

The nervous system is made up of the central nervous system and peripheral nervous system.

The peripheral nervous system is made up of the nerves that branches into the body from the spinal cord.

  • It consist of the somatic nervous system and the autonomous nervous system.
  • The somatic nervous system controls the voluntary actions of movement in the body.
  • It coordinates the reflex arc.

Learn more:

Nervous system brainly.com/question/4662759

#learnwithBrainly

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If the force of gravity acting on a box located near earths surface is 12.0 N, What’s it’s mass ?
Yuri [45]

Force of gravity on an object = (mass of the object) x (acceleration of gravity)


12.0 Newtons = (mass of the object) x (9.8 m/s²)


Mass of the object = (12.0 Newtons) / (9.8 m/s²)


Mass of the object = 1.22 kilograms

7 0
4 years ago
An 92-kg football player traveling 5.0m/s in stopped in 10s by a tackler. What is the original kinetic energy of the player? Exp
Artemon [7]

Explanation:

It is given that,

Mass of the football player, m = 92 kg

Velocity of player, v = 5 m/s

Time taken, t = 10 s

(1) We need to find the original kinetic energy of the player. It is given by :

k=\dfrac{1}{2}mv^2

k=\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2

k = 1150  J

In two significant figure, k=1.2\times 10^3\ J

(2) We know that work done is equal to the change in kinetic energy. Work done per unit time is called power of the player. We need to find the average power required to stop him. So, his final velocity v = 0

i.e. P=\dfrac{W}{t}=\dfrac{\Delta K}{t}

P=\dfrac{\dfrac{1}{2}\times (92\ kg)\times (5\ m/s)^2}{10\ s}

P = 115 watts

In two significant figures, P=1.2\times 10^2\ Watts

Hence, this is the required solution.  

6 0
3 years ago
An example of an opinion would be which of the following? bob s burgers is the best show on television. cake is appropriate for
muminat
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an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
Juli2301 [7.4K]

Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

To Find :

the image height (in cm).

Solution :

By lens formula :

\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Here, u = - 100 cm

f =  150 cm

\dfrac{1}{v} - \dfrac{1}{-100} = \dfrac{1}{150}\\\\v = - 300 \ cm

Now, magnification is given by :

m = \dfrac{v}{u} = \dfrac{h_i}{h_o}\\\\h_i = \dfrac{300}{100}\times 1\\\\h_i = 3 \ m

Therefore, the image height is 3 m or 300 cm.

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3 years ago
A girl is riding her bicycle. She rides 4 miles in 2.5 hours. What was her average speed?
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Explanation:

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