Question

A slender rod of length 80.0 cm and 0.600 kg has its center of gravity at its geometrical center. But its density is not uniform; it increases by the same amount from the center of the rod out to either end. You want to determine the moment of inertia Icm of the rod for an axis perpendicular to the rod at its center, but you don't know its density as a function of distance along the rod, so you can't use an integration method to calculate Icm. Therefore, you make the following measurements: You suspend the rod about an axis that is a distance d (measured in meters) above the center of the rod and measure the period T (measured in seconds) for small-amplitude oscillations about the axis. You repeat this for several values of d. When you plot your data as T2−4π2d/g versus 1/d, the data lie close to a straight line that has slope 0.470 m⋅s2. What is the value of Icm for the rod?

Answer 1

Answer:

Icm = 0.0701 kgm^2

Explanation: