Question

Part 1 :

Answer 1

1) 9.57 N

We have two forces applied on the apple:

- The force of gravity, in the downward direction:

W = 9.42 N

- The force exerted by the wind, in the horizontal direction (to the right):

Fw = 1.68 N

The two forces are perpendicular to each other, so we can find the magnitude of the net force by using Pythagorean's theorem.

Therefore, we have:

$F=\sqrt{W^2+F_w^2}=\sqrt{(9.42)^2+(1.68)^2}=9.57 N$

2) $10^{\circ}$

The direction of the net external force, measured from the downward vertical, can be measured using the following formula:

$\theta = tan^{-1}(\frac{F_x}{F_y})$

where

$F_x$ is the force in the horizontal direction

$F_y$ is the force in the vertical direction

In this problem,

$F_x = F_w = 1.68 N$

$F_y = W = 9.42 N$

and so we find:

$\theta = tan^{-1}(\frac{1.68}{9.42})=10^{\circ}$