When a scientific calculator shows the quantity below, what does it mean?<br> 1.5E8

How do I use the equation E=MC^2 in relation to atoms to find the amount of energy of a reaction?

Tomtit [17]

-- Find the mass of all the pieces before the reaction.

-- Find the mass of all the pieces after the reaction.

-- Find the difference . . . (mass before) minus (mass after)

-- If any mass is missing, either you lost track of it, or else
it was converted to energy.

How much energy ?

(the missing mass) times c² .

5 0

3 years ago

A rope attached to a sledge makes an angle of 40° with the ground. Calculate the tension in the rope required to produce a horiz

oksano4ka [1.4K]

let the tension force in the rope attached to the sledge be "T"

θ = angle of rope with the horizontal = 40 deg

X = horizontal component of tension force "T" = 100 N

horizontal component of tension force "T" is given as

X = T Cosθ

100 = T Cos40

T = 130.54 N

Y = vertical component of the tension force = ?

vertical component of the tension force is given as

Y = T Sinθ

inserting the values

Y = (130.54) Sin40

Y = 83.91 N

7 0

3 years ago

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.01 m l

Valentin [98]

Answer:

The strength of the magnetic field is $75.6\ \mu T$ .

Explanation:

Given that,

Length of the rod, L = 1.01 m

Speed with which the rod is moving, v = 3.47 m/s

We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :

$\epsilon=Blv$

B is magnetic field

$B=\dfrac{\epsilon}{lv}\\\\B=\dfrac{0.265\times 10^{-3}}{1.01\times 3.47}\\\\B=75.6\ \mu T$

So, the strength of the magnetic field is $75.6\ \mu T$ .

6 0

4 years ago

Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele

JulijaS [17]

Answer: $4.86(10)^{-12}m$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when photons are scattered is given by the following equation:

$\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda'=500 nm=500(10)^{-9} m$ is the wavelength of the scattered photon

$\lambda_{o}$ is the wavelength of the incident photon

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}.c}$ , being $h=4.136(10)^{-15}eV.s$ the Planck constant, $m_{e}$ the mass of the electron and $c=3(10)^{8}m/s$ the speed of light in vacuum.