Pe = mgh.
14000 J = (40kg)(10m/s^2)(h)
h = 35 meters
Answer: C: There is a high concentration of the Sun’s rays in that region.
I just took the test.
Explanation:
Answer: Example 1: Consider a crate being pulled along a frictionless floor (while such a floor is very hard to find, this will still help us understand the concept and we can return to this situation later, after considering friction, and solve it more realistically).
Consider a crate being pulled along a horizontal, frictionless floor. A rope is tied around it and a man pulls on the rope with a force of T. T is the tension in the rope. What happens to the crate?
Before we can apply Newton's Second Law,
F = m a
we must find the net force -- the vector sum of all the forces -- acting on the object. In addition to the force T exerted by the rope, what other forces act on the object?
As discussed in class, in Mechanics, we can restrict our attention to "contact" forces and "gravity". That means gravity pulls down on this crate with a force equal to its weight, w. But the floor supports the crate. The floor responds by pushing up on the crate with a force we call the normal force. "Normal" means "perpendicular". We will call this force n; you may also encounter it labeled N or FN.
Explanation:
Answer:
Pendulum B
Explanation:
The time period of a pendulum is given by :
Case 1.
Mass, m = 200 g = 0.2 kg
Length of string, l = 1 m
Time, 
T₁ = 2.007 Seconds
Since, 
f₁ = 0.49 Hz
Case 2.
Mass, m = 400 g = 0.4 kg
Length of string, l = 0.5 m
Time, 
T₂ = 1.41 seconds
f₂ = 0.709 seconds
Hence, pendulum B have highest frequency of vibration.
