Answer:
3100.05 N
Explanation:
= Force on piston = 45 N
= Radius of piston
= Radius of plunger

From Pascal's law we have

The force is 3100.05 N
Answer:

Explanation:
Given:
- dimension of square plate,

- thickness of fluid layer,

- force on the fluid due to plate,

- velocity of plate,

<u>Using Newton's law of viscosity:</u>
..........................................(1)
where:
shear force on the surface on the fluid
coefficient of (dynamic) viscosity
Now, shear force:


Putting respective values in eq.(1)


Answer:
B. 2nmv
Explanation:
Pressure is force over area.
P = F / A
Force is mass times acceleration.
F = ma
Acceleration is change in velocity over change in time.
a = Δv / Δt
Therefore:
F = m Δv / Δt
P = m Δv / (A Δt)
The total mass is nm.
The change in velocity is Δv = v − (-v) = 2v.
A = 1 and Δt = 1.
Plugging in:
P = (nm) (2v) / (1 × 1)
P = 2nmv
Answer:
Explanation:
The food chopping appliances in this scenario should adapt use of digital image processing systems to capture the images after the chopping begins. Certain variables can be defined like food particles size, area etc. This will help deciding a threshold for the variable and then the comparator used in the system will(run by real time operating system) compare the threshold size with the digital image size of particles. If the size is found small then the speed of motor should reduce meaning we have chopped the food as per our need. In case the chopping is not done aptly, the same can be enhanced by increasing the speed of motor till the final outcome is reached
Answer:
The options are not provided, so i will answer in a general way.
We know that:
The movement is along a straight horizontal surface, then we have one-dimensional motion.
The speed is 2m/s
We want a graph of position vs time.
Now, remember the relation:
Distance = Speed*Time
Then we can write the position as a function of time as:
P(t) = 2m/s*t + P0
Where t is our variable, that represents time in seconds, and P0 is the position at time t = 0seconds, we can assume that this is zero.
Then the equation is:
P(t) = 2m/s*t
And the graph is something like: