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2 years ago

7

A sample of helium gas at room temperature is compressed from 100 cm3 to 20 cm3. Its new pressure is now 30 cm Hg. What was the

original pressure of the gas?

1 answer:

andreev551 [17]2 years ago

5 0

Answer:

6 cm Hg

Explanation:

Boyles Law: P1V1=P2V2

(100 mL)(x)=(20 mL)(30 cm Hg)

x = 6 cm Hg

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

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allochka39001 [22]

Answer:

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Explanation:

SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

$1^{f} =\frac{Q}{m}$

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$m$ represents the mass of the object, in kg.

Now that we have our formula we just have to put our values into the formula:

$1^{f} =\frac{Q}{m}$

$1^{f} =\frac{863kJ}{4.6kg}$

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SO our answer would be $1^{f} =187.7 \frac{J}{kg}$

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