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KiRa [710]
3 years ago
11

A 100 g piece of aluminum is heated to 90°

Physics
1 answer:
Kisachek [45]3 years ago
8 0
<span>When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

Heat = mC(Tf-T)
6300 J = (100)(C)(90 - 20)
C = 0.9 J/g </span>°<span>C

Hope this answers the question. </span>
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The fact that desert sand is very hot in the day and very cold at night is evidence that sand has
insens350 [35]

Answer:

A) a low specific heat.

Explanation:

As we know that heat given to the sand will increase it temperature

so we can say

Q = ms\Delta T

here we will have

\Delta T = \frac{Q}{ms}

so now we will have

more change in temperature due to heat given to the sand will show that it must have low specific heat capacity as it inversely depends on the specific heat capacity of the sand

so correct answer will be

A) a low specific heat.

5 0
3 years ago
Read 2 more answers
A rubber toy duck is at rest on an inclined plane. When the angle of inclination of the plane is increased to 36.0°, the toy duc
ch4aika [34]

Answer

toy begins to slide when the plane is at an angle of 36.0°

at this point the toy has just overcome the static friction

f_s = \mu_s N

f_s = \mu_s mgcos \theta

since toy begins to slide

f_s = mgsin \theta

now on comparing

mgsin \theta = \mu_s mgcos \theta

\mu_s = tan \theta

\mu_s = tan (36^0)

\mu_s = 0.726

as the body is moving at constant velocity acceleration will be zero

so now,

m g sin \theta - f_k = ma

m g sin \theta - \mu_k mg cos\theta = 0

\mu_k = tan \theta

\mu_k = tan (29^0)

\mu_k = 0.554

3 0
3 years ago
Which process generates energy in the Sun?1) nuclear fusion2) nuclear fission3) chain reaction4) transmutation
Ber [7]

1) nuclear fusion

During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. During this process, radiant energy is released.

5 0
1 year ago
If you went to a planet that had the twice the radius as Earth, but the same mass, a 1 kg pineapple would have a weight of
kicyunya [14]

Use the law of universal gravitation, which says the force of gravitation between two bodies of mass <em>m</em>₁ and <em>m</em>₂ a distance <em>r</em> apart is

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

where <em>G</em> = 6.67 x 10⁻¹¹ N m²/kg².

The Earth has a radius of about 6371 km = 6.371 x 10⁶ m (large enough for a pineapple on the surface of the earth to have an effective distance from the center of the Earth to be equal to this radius), and a mass of about 5.97 x 10²⁴ kg, so the force of gravitation between the pineapple and the Earth is

<em>F</em> = (6.67 x 10⁻¹¹ N m²/kg²) (1 kg) (5.97 x 10²⁴ kg) / (6.371 x 10⁶ m)²

<em>F</em> ≈ 9.81 N

Notice that this is roughly equal to the weight of the pineapple on Earth, (1 kg)<em>g</em>, where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity, so that [force of gravity] = [weight] on any given planet.

This means that on this new planet with twice the radius of Earth, the pineapple would have a weight of

<em>F</em> = <em>G m</em>₁ <em>m</em>₂ / (2<em>r</em>)² = 1/4 <em>G m</em>₁ <em>m</em>₂ / <em>r</em>²

i.e. 1/4 of the weight on Earth, which would be about 2.45 N.

7 0
3 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
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