During which season is the sun highest in the sky?

$C_{1}$ $V_{1}$ = $C_{2}$ $V_{2}$ , where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

$C_{2}$ = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

$C_{2}$ = 288.9/205.0

Performing division on Right Hand Side

$C_{2}$ = 1.4%

Hence, the final concentration is 1.4%.

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The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

3 0

1 year ago

The solid product from reaction of sulfuric acid with sucrose is?

Mama L [17]

$\huge{\mathbb{\tt {QUESTION:}}}$

The solid product from reaction of sulfuric acid with sucrose is?

$\huge{\mathbb{\tt {ANSWER:}}}$

Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.

<h3>RELATED TO THE QUESTION </h3>

$\huge{\mathbb{\tt {What \: is \: solid?:}}}$

<u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
<u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.

$\huge{\mathbb{\tt {What \: is \: sulfur \: acid?}}}$

<u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.

$\huge{\mathbb{\tt{What \: is \: sucrose?}}}$

<u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.

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6 0

2 years ago

The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is Questio

Sphinxa [80]

Answer:

Heating this gas to 55 °C will raise its volume to 6.87 liters.

Assumption: this gas is ideal.

Explanation:

By Charles's Law, under constant pressure the volume $V$ of an ideal gas is proportional to its absolute temperature $T$ (the one in degrees Kelvins.)

Alternatively, consider the ideal gas law:

$\displaystyle V = \frac{n \cdot R}{P}\cdot T$ .

$n$ is the number of moles of particles in this gas. $n$ should be constant as long as the container does not leak.
$R$ is the ideal gas constant.
$P$ is the pressure on the gas. The question states that the pressure on this gas is constant.

Therefore the volume of the gas is proportional to its absolute temperature.

Either way,

$V\propto T$ .

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}$ .

For the gas in this question:

Initial volume: $V_1 = \rm 6.24\; L$ .

Convert the two temperatures to degrees Kelvins:

Initial temperature: $T_1 = \rm 25.0\;\textdegree{C} = (25.0 + {\rm 273.15})\; K = 298.15\;K$ .
Final temperature: $T_1 = \rm 55.0\;\textdegree{C} = (55.0 + {\rm 273.15})\; K = 328.15\;K$ .

Apply Charles's Law:

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 6.24\;L \times \frac{328.15\; K}{298.15\;K} = 6.87\;L$ .

7 0

4 years ago