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3 years ago

Answer the following question about the attached diagram:

Physics

2 answers:

alexgriva [62]3 years ago

8 0

Answer:

1) Image is formed at B

2) The image is an inverted real image

3) The image is a diminished image

4) The mirror is a concave mirror.

Explanation:

According to the diagram, object placed at this point in front of the curved mirror (concave) is placed beyond the center of curvature of the mirror.

To form images by an object placed in front of a curved mirror, ray diagrams are used.

According to the diagram, the first ray from the object incidented on the mirror and parallel to the principal axis converges at the focus (f) after reflection. The second incident ray pass through the focus and then reflect back with reflected ray parallel to the principal axis.

The two reflected ray intersects back at a point B according to the diagram and the image will be formed at that point B with the image head pointing towards the point of intersection.

According to the diagram above, the image will be formed at B and the nature of the image will be inverted, real, diminished (smaller than the object) and formed between the center of curvature and the focus of the mirror.

The mirror in the diagram is a concave mirror since the plane surface of the mirror is bent inwards.

Paladinen [302]3 years ago

3 0

I'm not entirely sure, but I think the first is A, and the second is inverted.

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The height of a helicopter above the ground is given by h = 2.65t3, where h is in meters and t is in seconds. at t = 1.55 s, the

lora16 [44]

Free fall is the motion of the body such that it is only acted upon by the force of gravity. Gravitational acceleration is normally 10 m/s² ,for a body in free fall the initial velocity (u) is 0.
Considering an equation of linear motion S= 1/2at² + ut but a=g and u=0
Therefore, S= 1/2gt², h (2.65 t³)= S = 2.65 ×1.55³ = 9.868
t² = 2S/g
t² = 9.868× 2/ 10
= 1.9736
t = √1.9736
Hence, the time taken will be equivalent to the sqrt of 1.9736 (√1.9736) which is equal to 1.405 seconds.

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4 years ago

The outer layer of bone _____.

baherus [9]

Answer:

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3 0

3 years ago

Suppose you have a car with a battery that applies 12.5 V to the starter.

Marat540 [252]

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

$V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega$

So, the resistance of the car's starter is 0.1 ohms.

7 0

3 years ago

You toss a ball straight up with an initial speed of 30m/s. How high does it go, and how long is it in the air (neglecting air r

Brut [27]

Explanation:

Given that,

A ball is tossed straight up with an initial speed of 30 m/s

We need to find the height it will go and the time it takes in the air.

At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :

v = u +at

Here, a = -g

v = u -gt

i.e. u = gt

$t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s$

So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds

Let d is the maximum distance covered by it.

$d=ut-\dfrac{1}{2}gt^2$

Putting all values

$d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m$

Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.

8 0

3 years ago

A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a tota

Dennis_Churaev [7]

Answer

D. The average speed is 2.5 meters/second, and the average velocity is 0 meters/second.

The difference between speed and velocity is that, speed is a scalar quantity while velocity is a vector quantity.

Average speed = total distance/Total time

= (150 + 150) / (2×60)

= 300/120

= 2.5 m/s

Average velocity = Total displacement/ Total time

= (150 + -150) / (2 × 60)

= 0/120

= 0 m/s

6 0

3 years ago