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Rina8888 [55]
3 years ago
13

Answer the following question about the attached diagram:

Physics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

1) Image is formed at B

2) The image is an inverted real image

3) The image is a diminished image

4) The mirror is a concave mirror.

Explanation:

According to the diagram, object placed at this point in front of the curved mirror (concave) is placed beyond the center of curvature of the mirror.

To form images by an object placed in front of a curved mirror, ray diagrams are used.

According to the diagram, the first ray from the object incidented on the mirror and parallel to the principal axis converges at the focus (f) after reflection. The second incident ray pass through the focus and then reflect back with reflected ray parallel to the principal axis.

The two reflected ray intersects back at a point B according to the diagram and the image will be formed at that point B with the image head pointing towards the point of intersection.

According to the diagram above, the image will be formed at B and the nature of the image will be inverted, real, diminished (smaller than the object) and formed between the center of curvature and the focus of the mirror.

The mirror in the diagram is a concave mirror since the plane surface of the mirror is bent inwards.

Paladinen [302]3 years ago
3 0
I'm not entirely sure, but I think the first is A, and the second is inverted.
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Answer: (a) Z-score are 1 and -1.2 for northern and southern regions, respectively.

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z=\frac{x-\mu}{\sigma}

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The z-score for birds living in the northern region is 1, which means it is 1 standard deviation <em>above the mean</em>.

For the southern region:

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z = -1.2

The z-score for southern living birds is -1.2, meaning it is 1.2 standard deviations <em>below the mean</em>.

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Please see attachment

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Please see attachment

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A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un
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Answer:

Explanation:

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r=r1+r2

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2 years ago
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Answer:

v = 0.5 m/s

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       \omega = \frac{\Delta\theta}{\Delta t} =  \frac{2*\pi}{2.4s} = 2.6 rad/sec (3)

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