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gizmo_the_mogwai [7]
3 years ago
13

What are the factor that affect gravity​

Physics
1 answer:
valentinak56 [21]3 years ago
6 0

Explanation:

The factors that affect gravity are as follows:

1. mass of body

2. acceleration

<em>Keep</em><em> </em><em>smiling </em><em>and</em><em> </em><em>hope</em><em> </em><em>u</em><em> </em><em>are</em><em> </em><em>satisfied</em><em> </em><em>with</em><em> </em><em>my</em><em> </em><em>answer</em><em>.</em><em>Have</em><em> </em><em>a</em><em> </em><em>good</em><em> </em><em>day</em><em> </em><em>:</em><em>)</em>

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The force of gravity on a person or object on the surface of a planet is called
viva [34]

Answer:

D. Weight

Explanation:

Hope that helps:)

3 0
3 years ago
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1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance o
adell [148]

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =k \frac{q_1q_2}{r^2}

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = k \ \frac{q^2}{r^2}

       q = \sqrt{\frac{F \ r^2}{k} }

we calculate

        q = \sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9}  }

        q = \sqrt{7 \ 10^{-12} }Ra 7 10-12

        q = 2.65 10⁻⁶ C

7 0
3 years ago
The _____________ variable is observed, measured, and affected by the independent variable.​
Katen [24]
The dependent variable
6 0
3 years ago
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Rafe is placing his car on a lift to change the oil and oil filter. He needs to drive up the lift 1.5 meters and the lift raises
jeyben [28]

Answer:

104 IMA

Explanation:

7 0
2 years ago
How do resistors in parallel affect the total resistance?
4vir4ik [10]

Answer:

They're going to increase the total resistance as R_{T} = \sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

Explanation:

If the resistors are in parallel, the potential difference is the same for each resistor. But the total current is the sum of the currents that pass through each of the resistors. Then

I = I_1 + I_2 + ... + I_N

where

I_i = \frac{V_i}{R_i}

but

V_i = V_j = V for i,j= 1, 2,..., N

so

I = \frac{V}{R_1}+ \frac{V}{R_2} + ... + \frac{V}{R_N} = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)V = \frac{V}{R_T}

where

R_T = \left(\frac{1}{R_1} +\frac{1}{R_2} + ... + \frac{1}{R_N}\right)^{-1} =\sum\limits_{i=1}^N \left(\frac{1}{R_i} \right)^{-1}

4 0
3 years ago
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