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Leno4ka [110]
3 years ago
7

An unknown or changeable quantity is called a(n)...

Chemistry
2 answers:
Natali [406]3 years ago
7 0
<h2>Answer:</h2>

An unknown and changeable quantity is known as an variable.

<h3>Explanation:</h3>

There are two types of quantities:

Constant quantities:

Quantities which can not be changed by changing physical parameters and their value is normally known.

Variable quantities:

These quantities can be changed by changing the physical parameters or conditions. Due to which they are unknown for particular conditions and have to be measured.

givi [52]3 years ago
6 0
It is called a variable
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you are holding a bowling ball with a mass of 6 kg at a height of 1 meter. How much gravitational potential energy does the bowl
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The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

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4 years ago
Given: 4Na + O2 → 2Na2O In this chemical reaction, how many moles of Na2O will be produced if 2.90 moles of Na react completely?
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Since we already have the balanced equation, we know that the ratio between Na:Na_{2}O is 4:2 respectively.

So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:

\frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}}

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4x=5.8

x=1.45

Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of Na_{2}O that are produced.

3 0
3 years ago
When the metal was placed in the calorimeter its
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Answer:

Exam 3 Material

Homework Page Without Visible Answers

This page has all of the required homework for the material covered in the third exam of the first semester of General Chemistry. The textbook associated with this homework is CHEMISTRY The Central Science by Brown, LeMay, et.al. The last edition I required students to buy was the 12th edition (CHEMISTRY The Central Science, 12th ed. by Brown, LeMay, Bursten, Murphy and Woodward), but any edition of this text will do for this course.

Note: You are expected to go to the end of chapter problems in your textbook, find similar questions, and work out those problems as well. This is just the required list of problems for quiz purposes. You should also study the Exercises within the chapters. The exercises are worked out examples of the questions at the back of the chapter. The study guide also has worked out examples.

These are bare-bones questions. The textbook questions will have additional information that may be useful and that connects the problems to real life applications, many of them in biology.

Explanation:

5 0
2 years ago
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Help please I’m stuck on thsi question
vodomira [7]
Since it’s asking for chemical to thermal, B.
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3 years ago
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A substance having
denpristay [2]

Explanation:

Specific heat capacity is how much is required to heat the unit of mass by one degree. Therefore, if you have a higher heat capacity it required more energy, therefore, it takes longer to heat up. whereas having a lower heat capacity it takes less time to best up as it requires less energy.

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