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-BARSIC- [3]
2 years ago
10

What is the volume of 8.7 * 10 ^ 23 molecules of chlorine gas (Cl 2 ) ?

Chemistry
1 answer:
Mariana [72]2 years ago
8 0

Answer:

32.3 dm³

Explanation:

Data given:

no. of molecules of Cl₂ = 8.7 x 10²³

Volume of chlorine gas (Cl₂) = ?

Solution:

First we have to find number of moles

For this formula used

    no. of moles = no. of molecules / Avogadros number

    no. of moles = 8.7 x 10²³ / 6.022 x 10²³

    no. of moles = 1.44 moles

Now we have to find volume of the gas

for this formula used

                      no. of moles = volume of gas / molar volume

molar volume = 22.4 dm³/mol

Put values in above equation

                 1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol

rearrange the above equation

                 volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol

                volume of Cl₂ gas =  32.3 dm³

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What we need to find the pKa of the weak acid, in this case NaH2PO4, for that you need to find the Ka (acid constant) of NaH2PO4, and for this we use the pKa of the phosphoric acid as follow:

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So, for the preparation of buffer, you need to use the pKa that is near to the value of the pH that you want, so the choice will be:

pKa2= 6.86

Now we going to use the Henderson Hasselbalch equation for the pH of a buffer solution:

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The solution of the problem is attached to this answer.

Download odt
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