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3 years ago

Which describes a force acting on an object?

Physics

1 answer:

weeeeeb [17]3 years ago

3 0

Answer:

Describing a Force:

To fully describe the force acting upon an object, you must describe both its magnitude and direction. Thus, 10 Newtons of force is not a complete description of the force acting on an object. 10 Newtons, downwards is a complete description of the force acting upon an object.

Explanation:

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An ideal gas is sealed in a container at constant volume. if the temperature t is increased to 4t, the pressure will be:

Westkost [7]

I believe that it would increase to 4p

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3 years ago

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A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars becom

Ivanshal [37]

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

$p_i = p_f$

$m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v$

where

$m_1 = 10,000 kg$ is the mass of the first car

$u_1=30 m/s$ is the initial velocity of the first car

$m_2 = 20,000 kg$ is the mass of the second car

$u_2 = 0$ is the initial velocity of the second car

$v$ is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

$v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(10,000)(30)-0}{10,000+20,000}=10 m/s$

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3 years ago

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APPLIC

sergeinik [125]

Answer:

1.43 x1000=1430

Explanation:

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3 years ago

A car advertisement states that a car can accelerate at 2 m/sec. The car starts from rest and accelerates to 70 km/hr. How much

Reptile [31]

Answer:

9.72s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A car starts from rest.}\\\textsf{It has an acceleration of 2m/s$^2$.}\\\textsf{ The final velocity of the car is 70km/hr.}\end{cases}$

Here we need to find out the time that the car took to achieve the velocity of 70km/hr after starting from rest . Firstly convert the final velocity in m/s by multiplying it by 5/18 , as ,

$\longrightarrow\sf 70km/hr = 70 \times \dfrac{5}{18} m/s =\bf 19.44\ m/s$