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MArishka [77]
3 years ago
12

Which describes a force acting on an object?

Physics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

Describing a Force:

To fully describe the force acting upon an object, you must describe both its magnitude and direction. Thus, 10 Newtons of force is not a complete description of the force acting on an object. 10 Newtons, downwards is a complete description of the force acting upon an object.

Explanation:

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An ideal gas is sealed in a container at constant volume. if the temperature t is increased to 4t, the pressure will be:
Westkost [7]
I believe that it would increase to 4p
6 0
3 years ago
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A 10,000-kg railroad car travels down the track at 30 m/s and hits a second stationary railroad car of 20,000 kg. The cars becom
Ivanshal [37]

Answer:

10 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following

p_i = p_f

m_1 u_1 + m_2 u_2 = (m_1 +m_2 )v

where

m_1 = 10,000 kg is the mass of the first car

u_1=30 m/s is the initial velocity of the first car

m_2 = 20,000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v is the final velocity of the two combined cars after the collision

Re-arranging the equation and substituting the numbers, we find

v=\frac{m_1 u_1 +m_2 u_2}{m_1+m_2}=\frac{(10,000)(30)-0}{10,000+20,000}=10 m/s


6 0
3 years ago
Read 2 more answers
APPLIC
sergeinik [125]

Answer:

1.43 x1000=1430

Explanation:

8 0
3 years ago
A car advertisement states that a car can accelerate at 2 m/sec. The car starts from rest and accelerates to 70 km/hr. How much
Reptile [31]

Answer:

9.72s

Explanation:

\pink{\frak{Given}}\begin{cases}\textsf{ A car starts from rest.}\\\textsf{It has an acceleration of 2m/s$^2$.}\\\textsf{ The final velocity of the car is 70km/hr.}\end{cases}

Here we need to find out the time that the car took to achieve the velocity of 70km/hr after starting from rest . Firstly convert the final velocity in m/s by multiplying it by 5/18 , as ,

\longrightarrow\sf 70km/hr = 70 \times \dfrac{5}{18} m/s =\bf 19.44\  m/s

  • As we know that the rate of change of velocity is known as acceleration , so ;

\longrightarrow\sf a =\dfrac{v - u}{t}

Plug in the respective values ,

\longrightarrow\sf 2m/s^2 = \dfrac{ 19.4 m/s -0m/s}{t} \\

Simplify ,

\longrightarrow\sf 2m/s^2 =\dfrac{19.4m/s}{t}

Cross multiply ,

\longrightarrow\sf t = \dfrac{19.44m/s}{2m/s^2}

Simplify

\longrightarrow\sf \boxed{\bf t = 9.72 s}

<h3>Hence the required answer is 9.72s.</h3>
7 0
2 years ago
four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m. a 3.00kg object is at +2.50m, a 2.50kg obje
Mashutka [201]

The centre of mass of the objects is (0,1)m .

What do you mean by Centre of mass?

The centre of mass is a position defined relative to an object or system of objects .

We have given

m1=2kg , y1= 3

m2= 3kg ,y2=2.5m

m3=2.5kg ,y3= 0m

m4=4kg , y4= -0.5m

Ycm=mixi/mi

→2×3+3×2.5+2.5×0+4×0.5/4.5

→1m

Centre of mass of these object is at (0,1)m .

to learn more about centre of mass click herehttps://brainly.com/question/19426784

#SPJ9

4 0
2 years ago
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