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LekaFEV [45]
3 years ago
12

The altitude of a triangle is 6 cm greater than its base .if its area is 108 cm ,find its base

Mathematics
1 answer:
xeze [42]3 years ago
6 0

Area of the triangle = (1/2)*base*height

base = x

height = altitude = x+6

Area of the triangle = (1/2)*x*(x+6) = 108

(1/2)*x*(x+6) = 108

x²+6x-216 =0

(x+18)(x-12)=0

x=-18, or x=12

We can use only positive value, so x=12.

Base =12 cm.


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a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

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Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
3 years ago
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