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Irina18 [472]
3 years ago
15

Given the exponential equation, 3=18. Which of the equationsbelow will solve for x?

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

if you are evaluating this claim is false

You might be interested in
Simplify (5^-2)^4. Plsss help
Oksana_A [137]

Answer:

1/5^8

Step-by-step explanation:

We know that a^b^c = a^(b*c)

(5^-2)^4

5^(2*-4)

5^-8

We know that a^-b = 1/a^b

1/5^8

7 0
2 years ago
Estimate the product of 2.28 × 5.59 using compatible numbers.
Ierofanga [76]

The quotient of 2.28 × 5.59 using compatible numbers is approximately 12.75

<h3>What are products?</h3>

Quotients are result derived from the multiplication of two rational or integers. Given the expression

2.28 × 5.59

Convert to fraction

2.28 × 5.59 = 228/100  ÷  559/100
2.28 × 5.59= 127452/10000

2.28 × 5.59=  12.75

Hence the quotient of  2.28 × 5.59  using compatible numbers is approximately 12.75

Learn more on product here: brainly.com/question/673545

#SPJ1

3 0
2 years ago
A motorcyclist leaves City A and rides at a constant speed towards City B, which is 225 km away. After 1.5 hours, the motorcycli
rewona [7]

Answer:

50 km/hr

Step-by-step explanation:

OK, this is how I solved this problem.

Let r = original rate of speed

     t = time after the stop to finish the trip

Time for trip without stopping is 225/r

(1)     1.5 + .5 + t = 225/r      This is a time equation

(2)    1.5r + t(r + 10) = 225     This is a distance equation

(1)       2 + t = 225/r            (2)      1.5r + tr + 10t = 225

         2r + tr = 225

                tr = 225 - 2r                 1.5r + 225 - 2r + 10(225/r - 2) = 225

                t = 225/r - 2

                                                   -.5r + 225 + 2250/r - 20 = 225

                                                     -5r + 2250 + 22500/r - 200 = 2250

                                                     -5r^2 + 2250r + 22500 - 200r = 2250r

                                                       5r^2 + 200r - 22500 = 0

                                                       5(r^ + 40r - 4500) = 0

                                                           5(r - 50)(r + 90) = 0

                                                                 r = 50   or    r = -90

The rate cannot be negative, so the original speed 50 km/hr

This not an easy problem and I hope you were able to follow my work

5 0
3 years ago
Read 2 more answers
Can anyone help me out with this math problem?
inna [77]
The slope is negative
8 0
3 years ago
I need help on this?!
Sergio039 [100]
If you nee solving it will be:
c^6(-3c^5)^2
c^6(3c^5)^2
c^6·3^2(c^5)^2
c^6·9(c^5)^2
c^6·9c^10
9c^6c^10
9c^6+10
9c^16
So the answer is:
9c^16
(9c to the power of 16)
Sorry I was late..
3 0
3 years ago
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