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Bezzdna [24]
3 years ago
13

Which of the following coefficients will correctly

Chemistry
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

#2 is the answer

Bcuz 2 times 2 = 4

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What suffix do the halogen group use
sesenic [268]

Answer:    That is, the suffix of the compound is unchanged by the presence of the halogen, and the halogen is included as a prefix in the name. In acyl halides, the suffix -oyl chloride is appended to the name. For example, CH3CH2COCl is called propanoyl chloride.

Explanation:

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2 years ago
Which method is used to obtain petrol from petroleum?
kotykmax [81]

Explanation:

fractional distillation method is used to obtain petrol from petroleum...

hope it helps

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A rectangular fence is 3 times as long as it is wide. The perimeter is 60ft. Find the dimensions of the fence
Mashutka [201]

Answer:

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

Explanation:

To solve this problem we will turn this question into an equation.

The equation for the perimeter of a rectangle is 2l + 2w = perimeter.

In the question we were given the perimeter so we can go ahead and plug this in.

2l + 2w = 60

In the question we are also told that the fence is 3 times as long as it is wide. This means that 1l = 3w. We can now subsitute l for 3w so that we only have one variable.

2(3w) + 2w = 60

Now we can simply use algebra to solve for w.

6w + 2w = 60

8w = 60

w = 7.5

Now that we know the value of w we can find the value of l since we know 1l = 3w.

l = 3w

l = 3(7.5)

l = 22.5

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

7 0
3 years ago
In an experiment to study the photoelectric effect, a scientist measures the kinetic energy of ejected electrons as afunction of
crimeas [40]

Answer:

a) v₀ = 4.41 × 10¹⁴ s⁻¹

b) W₀ = 176 KJ/mol of ejected electrons

c) From the graph, light of frequency less than v₀ will not cause electrons to break free from the surface of the metal. Electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. Explanation is in the section below.

Explanation:

The plot for this question which is attached to this solution has Electron kinetic energy on the y-axis and frequency of incident light on the x-axis.

a) Wavelength, λ = 680 nm = 680 × 10⁻⁹ m

Speed of light = 3 × 10⁸ m/s

The frequency of the light, v₀ = ?

Frequency = speed of light/wavelength

v₀ = (3 × 10⁸)/(680 × 10⁻⁹) = 4.41 × 10¹⁴ s⁻¹

b) Work function, W₀ = energy of the light photons with the wavelength of v₀ = E = hv₀

h = Planck's constant = 6.63 × 10⁻³⁴ J.s

E = 6.63 × 10⁻³⁴ × 4.41 × 10¹⁴ = 2.92 × 10⁻¹⁹J

E in J/mol of ejected electrons

Ecalculated × Avogadros constant

= 2.92 × 10⁻¹⁹ × 6.023 × 10²³

= 1.76 × 10⁵ J/mol of ejected electrons = 176 KJ/mol of ejected electrons

c) Light of frequency less than v₀ does not possess enough energy to cause electrons to break free from the metal surface. The energy of light with frequency less than v₀ is less than the work function of the metal (which is the minimum amount of energy of light required to excite electrons on metal surface enough to break free).

As evident from the graph, electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. From the mathematical relationship, E = hv₀,

And the slope of the line segment is Energy of ejected electrons/frequency of incident light, E/v₀, which adequately matches the Planck's constant, h = 6.63 × 10⁻³⁴ J.s

Hope this Helps!!!

5 0
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What is the element name for 2,2​
Strike441 [17]

Answer:

Helium

Explanation:

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