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lisov135 [29]
3 years ago
6

In which of these star groups would you mostly likely find the least heavy-element abundance for the stars within them: open clu

sters, globular clusters, or associations?
Physics
1 answer:
djyliett [7]3 years ago
8 0

Answer: globular clusters

Explanation:

A globular cluster is a star which is usually spherical, it’s a collection of stars which is known to orbits a galactic core. Globular clusters are usually very tightly bound together by gravity, this helps in giving them their spherical shapes which they are known for, and it’s relatively high stellar densities which is found toward their centers.

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Which statement correctly stated kepler's 3rd law of planetary motion?
nadya68 [22]
When you square the "year" of each planet and divide it by the cube of its distance, or axis from the sun, the number would be the same for all the planets
8 0
3 years ago
Read 2 more answers
The gravitational force experienced by Earth due to the Moon is ________ the gravitational force experienced by the Moon due to
Vsevolod [243]

The gravitational force experienced by Earth due to the Moon is <u>equal to </u>the gravitational force experienced by the Moon due to Earth.

<u>Explanation</u>:

The force that attracts any two objects/bodies with mass towards each other is defined as gravitational force. Generally the gravitational force is attractive, as it always pulls the masses together and never pushes them apart.

The gravitational force can be calculated effectively using the following formula: F=GMmr^2  

where “G” is the gravitational constant.

Though gravity has the ability to pull the masses together, it is the weakest force in the nature.

The mass of the Earth and moon varies, but still the gravitational force felt by the Earth and Moon are alike.

5 0
3 years ago
A bar magnet is held above the center of a conducting ring in the horizontal plane. The magnet is dropped so it falls lengthwise
Alenkinab [10]

Explanation:

Since, it is given that the magnet drops and falls lengthwise towards the canter of the ring. As a result, change in magnetic flux will occur which tends to induce an electric current in the ring.

Therefore, a magnetic field is also produced by the ring itself which will actually oppose or repel the magnet.  

Thus, we can conclude that the falling magnet be repelled by the ring due to the magnetic interaction of the magnet and the ring.

7 0
3 years ago
When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc
OleMash [197]

Answer:

T = 4.48 s

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}

so the time period of the oscillation is given as

T = 2\pi \sqrt{\frac{L}{g}}

so we will have

L = 5 m

T = 2\pi\sqrt{\frac{5}{9.81}}

T = 4.48 s

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0
3 years ago
An airplane is flying in the direction 10° east of south at 701 km/hr. Find the component form ofthe velocity of the airplane, a
solniwko [45]

Answer:

The component form will be;

In the x-axis = 121.73 due west

In the y-axis = 690.35 due south

Explanation:

An image of the calculation has been attached

7 0
3 years ago
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