Answer:
Assuming the charged density in the insulated solid sphere of radius 3.1m is 8.8e-9, the electric field at 5.2 meters is 73.1256 .
Explanation:
The electric charge linear density is equal to 8.8 x
the radius of the sphere is 3.1m
The magnitude of the electric field at the radius of the sphere equal to 5.2 meters can be calculated with the formula ;
- E = λ / 4πε₀ [ r / α ( α + r ) ]
Solution:
E = 8.8 x / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ]
= 1018.0995 [0.07183]
= 73.1256
Answer:1.513 rps
Explanation:
Given
Diameter of cylindrical space
When the station rotates it creates centripetal acceleration which is given by
Now it must create the effect of gravity so
and
Thus
Answer:
2.22 m
Explanation:
According to literature, the highest abrupt deceleration the human body can experience and survive in a car accident is 250 m/s²
Using the equations of motion,
v² = u² + 2as
v = final velocity of the body = 0 m/s
u = initial velocity of the body = 120 km/h = 120 × 1000/3600 = 33.33 m/s
a = - 250 m/s²
s = ?
0² = 33.33² - (2×250×s)
500s = 1111.1111
s = 2.22 m
Answer:
The top of the window is 0.5 m below the sill of the upper window
Explanation:
We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward
y-yo=vo*t+I/2gt^2
vo=(y-yo-I/2gt^2)/t
vo=3.138 m/s
The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.
v^2=vo^2+2g(y-yo)
y-yo=(v^2-vo^2)/2g
= 0.5 m
The top of the window is 0.5 m below the sill of the upper window