B <span> of Earth’s surface is covered by water. Very little or no light penetrates beyond a few hundred feet in water</span>
To solve the problem it is necessary to apply the concepts related to Kepler's third law as well as the calculation of distances in orbits with eccentricities.
Kepler's third law tells us that

Where
T= Period
G= Gravitational constant
M = Mass of the sun
a= The semimajor axis of the comet's orbit
The period in years would be given by

PART A) Replacing the values to find a, we have




Therefore the semimajor axis is 
PART B) If the semi-major axis a and the eccentricity e of an orbit are known, then the periapsis and apoapsis distances can be calculated by



Answer:

Explanation:
From the question we are told that:
Radius 
Current 
Normal vector 
Magnetic field 
Generally the equation for Area is mathematically given by



Generally the equation for Torque is mathematically given by

Where

![X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]](https://tex.z-dn.net/?f=X%5C%20component%5C%20of%5C%20i%27%2AB%3D%20%5B%28-1%20%2A%200%29-%282%2A-6%29%5D)

Therefore

