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3 years ago

How many significant figures are there in this expression 0.001050

2 answers:

8 0

1.all non zero digit are significant
2.zero b/w non-zero digits are significant
3.if number is less than 1 zero on right of decimal point but to the left of first non-zero digit are not significant

here 4 significant figures are there in 0.001050
123 -3 significant figures
123000-3 significant figures
2.107 - 4 significant figures
0.5610 - 4 significant figures

WITCHER [35]3 years ago

4 0

4 sig fig in that expression

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When would a life scientist study a nonliving thing such as a rock or lake

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He would study it so he could see how it interacted with the living things around it.

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3 years ago

A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58

Scilla [17]

Answer:

$\% O=27.6\%$

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

$n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC$

- Moles of hydrogen are contained in the 3.922 grams of water:

$n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH$

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

$m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO$

Finally, we compute the percent by mass of oxygen:

$\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%$

Regards.

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3 years ago

What are the gas laws? (Include Boyle's law, charles's law, gay lussac's law, an avogadro's law) Could someone please summarize

Rina8888 [55]

Answer:

Boyle's Law: When the pressure of a gas increases, the volume of the gas will decrease as long as the temperature and amount of gas are constant.

So basically pressure is inversely proportional to Volume, when one increases, the other decreases, vice versa.

Equation: $P_{1} V_{1} = P_{2} V_{2}$

Charles Law: When the temperature of a gas increases, the volume of a gas will also increase if the pressure and amount of gas are constant.

So basically Temperature and volume are directly proportional.

Equation: $\frac{V_{1}}{T_{1}} = \frac{V_{2} }{T_{2} }$

Gay Lussac's Law: When the temperature of a gas increases, the pressure of a gas also increases when volume and the amount of gas remain constant.

Basically, Temperature and Pressure are directly proportional.

Equation: $\frac{P_{1}}{T_{1}} = \frac{P_{2} }{T_{2} }$

Avogadro's Law: The most intuitive gas law. When you increase the amount of gas, the volume will also increase.

Meaning the moles (amount of gas) is directly proportional to volume.

Equation: $\frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} }$ (n stands for moles)

There is a combined gas law and ideal gas law but those are just the gas laws mentioned above but combined together. These should be everything.

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2 years ago

Read 2 more answers

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finlep [7]

<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

$reactants$ → $products$

$reactants$ refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

$products$ refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are written on the right side of the equation.

So, $Ca_{3}(PO_{4})_{2}$ , $H_{2}O$ are the products.

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3 years ago

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podryga [215]

Answer:

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