Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.
Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.
It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.
Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.
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Answer:
See explaination
Explanation:
please kindly see attachment for the step by step solution of the given problem.
Answer:
required feedback resistance ( R2 ) = 100 k Ω
Explanation:
Given data :
Voltage gain = 100
input resistance ( R1 ) = 1 k ohms
calculate feedback resistance required
voltage gain of differential amplifier
= Voltage gain = R2/R1
= 100 = R2/1
hence required feedback resistance ( R2 ) = 100 k Ω
Answer:
The solution code is written in Java.
- public class Movie {
- private double [][] seats = new double[5][5];
- private double totalSales;
-
- public Movie(){
-
- for(int i= 0; i < this.seats.length; i++){
- for(int j = 0; j < this.seats[i].length; j++){
- this.seats[i][j] = 12;
- }
- }
-
- this.totalSales = 0;
- }
-
- public boolean bookSeat(int i, int j)
- {
- if(this.seats[i][j] != 0){
- this.totalSales += this.seats[i][j];
- this.seats[i][j] = 0;
- return true;
- }else{
- return false;
- }
-
- }
- }
Explanation:
The method, bookSeat(), as required by the question is presented from Line 16 - 26 as part of the public method in a class <em>Movie</em>. This method take row,<em> i</em>, and column,<em> j</em>, as input.
By presuming the seats is an two-dimensional array with all its elements are initialized 12 (Line 7 - 10). This means we presume the movie ticket price for all the seats are $12, for simplicity.
When the<em> bookSeat() </em>method is invoked, it will check if the current price of seats at row-i and column-i is 0. If not, the current price, will be added to the <em>totalSales </em>(Line 19)<em> </em>and then set the price to 0 (Line 20) and return <em>true</em> since the ticket is successfully sold (Line 21). If it has already been sold, return <em>false</em> (Line 23).
Answer:
a) the object floats
b) the object floats
c) the object sinks
Explanation:
when an object is less dense than in the fluid in which it is immersed, it will float due to its weight and volume characteristics, so to solve this problem we must find the mass and volume of each object in order to calculate the density and compare it with that of water
a)
volumen for a cube
V=L^3
L=1.53in=0.0388m
V=0.0388 ^3=5.8691x10^-5m^3=58.69ml
density=m/v
density=13.5g/58.69ml=0.23 g/ml
The wooden block floats because it is less dense than water
b)
m=111mg=0.111g
density=m/v
density=0.111g/0.296ml=0.375g/ml
the metal paperclip floats because it is less dense than water
c)
V=0.93cups=220.0271ml
m=0.88lb=399.1613g
Density=m/v
density=399.1613/220.027ml=1.8141g/ml
the apple sinks because it is denser than water
