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Alina [70]
3 years ago
13

A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion

10.5 kJ/g. Calculate the heat capacity of the calorimeter apparatus in kJ/0C
Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

A 1.0 g sample of propane, C3H8, was burned in the calorimeter.

The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.

Calculate the heat capacity of the calorimeter apparatus in kJ/0C

Explanation:

Heat of combustion = heat capacity of calorimeter * deltaT\\

Given,

The heat of combustion = 10.5kJ/g.

deltaT = (32.0-28.5)^oC\\deltaT = 3.5^oC

Substitute these values in the above formula to get the value of heat capacity of the calorimeter.

deltaT =heat  capacity of calorimeter   * (change in temperature)\\10.5kJ/g = heat  capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC

Answer:

The heat capacity of the calorimeter is 3.0kJ/g.^oC.

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