Answer:
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Explanation:
https://doubtnut.app.link/FnsNC80Dccb
<span>1.0x10^3 Joules
The kinetic energy a body has is expressed as the equation
E = 0.5 M V^2
where
E = Energy
M = Mass
V = Velocity
Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion
E = 0.5 * 7.2 kg * (17 m/s)^2
E = 3.6 kg * 289 m^2/s^2
E = 1040.4 kg*m^2/s^2
E = 1040.4 J
So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>
Gravitational potential energy can be calculated using the formula <span>PE = m × g × h, where g is the gravitational acceleration and is constant hence the energy is dependent directly to mass and the height of the object. Hence more PE is registered when the object is heavier and/or at greater initial height. </span>
Answer:
Explanation:
We have here values from SI and English Units. I will convert the units to English Units.
We hace for the power P,


we have other values such
and
(specific weight of the water), and 0.85 for \eta
We need to figure the flow rate of the water (V) out, that is,

Where
is the turbine efficiency, at which is,

Replacing,


With this value (the target of this question) we can also calculate the mass flow rate of the waters,
through the density and the flow rate,

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,
