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AleksandrR [38]
3 years ago
10

What is the density of the baseball?

Physics
2 answers:
Georgia [21]3 years ago
7 0

Answer:

Chile the answer is yes

Explanation:

I just took the quiz

Aleksandr [31]3 years ago
5 0

The density of the baseball is 0.875 g/cm^3

Explanation:

The density of an object is given by the equation

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

For the baseball in this problem, we have:

m = 350 g is its mass

V=400 mL = 400 cm^3 is the volume

Substituting into the equation, we find the density:

d=\frac{350}{400}=0.875 g/cm^3

Therefore, the ball's density is outside the acceptable range.

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

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A(n) 2602 kg van runs into the back of a(n)
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Solid materials that do not possess an orderly arrangement of atoms are called
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Answer:

Solid materials that do not possess an orderly arrangement of atoms are called glasses (mineraloids).

Explanation:

A Mineraloid is a natural, inorganic, amorphous (lacking "defined chemical composition") solid body that does not exhibit crystallinity. It exhibits characteristics similar to those of minerals, but does not have the "ordered atomic structure" necessary to meet the definition of a mineral.

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4 0
3 years ago
A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed on 10 m/s. If air
fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

v_x = 10 m/s

Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

d=(10)(2.02)=20 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
Against the wind a commercial airline in south america flew 784 miles in 4 hours. with a tailwind the return trip took 3.53 hour
ira [324]

First let us assign variables,

d = distance travelled

t = time it took

v = velocity of the commercial airline

In linear physics, the equation for velocity is given as:

v = d / t

Rewriting for d:

d = v t

We know that the distance to and from south America are equal therefore:

d1 (going) = d2 (return)

Let us say that velocity of air is v3. Since going to South America, the wind is against the direction of the plane and the return trip is the opposite, therefore:

(v1 - v3) t1 = (v1 + v3) t2

(v1 – v3) 4 = (v1 + v3) 3.53

4 v1 – 4 v3 = 3.53 v1 + 3.53 v3

0.47 v1 = 7.53 v3

v1 = 16.02 v3

Since we also know that:

(v1 - v3) t1 = 784

(16.02 v3 – v3) * 4 = 784

60.085 v3 = 784

v3 = 13.05 mph

Therefore the speed of the plane in still air, v1 is:

v1 = 16.02 * 13.05

<span>v1 = 209.03 mph           (ANSWER)</span>

<span> </span>

4 0
3 years ago
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