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2 years ago

how much horse power is needed to move a box that has a force of 1,492 newtons a distance of 2 meters in 1 second

1 answer:

5 0

This one is a piece 'o cake if you know the definition
of a horsepower, and impossible if you don't.

It is: 1 horsepower = 746 watts

Also, remember that 1 watt = 1 joule/second

Now: Work = (force) x (distance)

To move this box 2 meters,

   Work = (1,492 newtons) x (2 meters) = 2,984 joules

If you accomplished that feat in 1 second,
then you produced power of

   (2,984 / 1) (joule/second) = 2,984 watts .

   (2,984 watt) x (1 HP / 746 watt) = 4 horsepower .

That's the solution, applying bullet-proof math and physics to the
given data. But in the real world, I guarantee that you didn't do that.
______________________________________

By the way ... a comment regarding the terminology in the question:

The box doesn't "have a force" of 1,492 newtons. That's the force
with which you ... or a horse, or an ox ... pushed against the box
in order to move it.

(And, if I might observe, that force is about 336 pounds,
so my money would be on the horse or the ox.)

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light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to

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3 years ago

Read 2 more answers

A bicyclist starting at rest produces a constant angular acceleration of 1.30 rad/s2 for wheels that are 35.5 cm in radius.

Debora [2.8K]

Answer:

a) 0.462 m/s^2

b) 31.5 rad/s

c) 381 rad

d) 135m

Explanation:

the linear acceleration is given by:

$a=\alpha *r\\a=1.30rad/s^2*(35.5*10^{-2}m)\\a=0.462m/s^2$

the angular speed is given by:

$\omega=\frac{v}{r}\\\\\omega=\frac{11.2m/s}{35.5*10^{-2}m}\\\\\omega=31.5rad/s$

to calculate how many radians have the wheel turned we need the apply the following formula:

$\theta=\frac{1}{2}\alpha*t^2\\\\t=\frac{\omega}{\alpha}\\\\t=\frac{31.5rad/s}{1.30rad/s^2}\\\\t=24.2s\\\\\theta=\frac{1}{2}*1.30rad/s^2*(24.2s)^2\\\\\theta=381rad$

the distance is given by:

$d=\theta*r$

$d=381rad*(35.5*10^{-2}m)\\d=135m$

4 0

3 years ago

A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the

jasenka [17]

Answer:

1.8 cm

Explanation:

$m$ = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

$q$ = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

$\Delta V$ =Potential difference through which the ion is accelerated = 215 V

$v$ = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

$(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}$

$r$ = Radius of the path followed by ion

$B$ = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

$qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm$

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2 years ago

Hooke's Law Practice

Oxana [17]

Answer:sheeExplanation:

8 0

2 years ago

hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N

Airida [17]

Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

m = mass

a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N

8 0

2 years ago