Question

You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You discover that the balloon bursts when you have pitched it to a height of 10 m.
with what velocity did the ballon hit the ground? The acceleration of gravity is 9.8 m/s^2. The positive direction is up, to the velocity when it hits is negative. An

Answer 1

Answer:

this is correct

Explanation:

Answer 2

It is given that the balloon fell from a height of 10 m.

So, its displacement in the vertical direction h = -10 m, because the question specifically asks us to take the upward direction as +.

Acceleration in the vertical direction  $a_{y} = -9.8 m/s^{2}$

Since the balloon dropped from a given height, its initial velocity $V_{i} = 0$

Final Velocity $V_{f} = ?$

Using the equation  $V^{2} _{f} = V^{2} _{i} + 2(a_{y} )(h)$

and plugging in the known values, we get  [tex]V^{2} _{f} = 0 + 2(- 9.8)(- 10)

Solving this for  [tex]V_{f}, we get [tex]V_{f} = 14 m/s or [tex]V_{f} = -14 m/s

Since the question is asking us for the final velocity, which faces downward direction, we choose [tex]V_{f} = -14m/s as the final answer.