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Grace [21]
3 years ago
14

A 24.0 cm long screwdriver is used as a lever to open a can of paint. If the fulcrum is 0.500 cm away from the end of the screwd

river, what is the screwdriver's ideal mechanical advantage?
Physics
1 answer:
ELEN [110]3 years ago
7 0

The ideal mechanical advantage of the screwdriver is 47

Explanation:

In this problem, the screwdriver acts as a lever.

The Ideal Mechanical Advantage (IMA) of a lever is given by:

IMA=\frac{d_i}{d_o}

where:

d_i is the distance of the point of application of the input force from the fulcrum

d_o is the distance of the output force from the fulcrum

In this problem, we have:

d_o = 0.500 cm, since the fulcrum is 0.500 cm from the end

d_i = 24.0 cm - 0.500 cm = 23.5 cm (the distance between the fulcrum and the point where are we holding the screwdriver)

Substutiting,

IMA=\frac{23.50 cm}{0.50 cm}=47

Learn more about levers here:

brainly.com/question/5352966

#LearnwithBrainly

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3 years ago
An electron moving parallel to a uniform electric field increases its speed from 2.0 × 107 m/s to 4.0 × 107 m/s over a distance
jeka94

Answer:

1.8\times 105 N/C

Explanation:

We are given that

u=2\times 10^7 m/s

v=4\times 10^7 m/s

d=1.9 cm=\frac{1.9}{100}=0.019 m

Using 1m=100 cm

We have to find the electric field strength.

v^2-u^2=2as

Using the formula

(4\times 10^7)^2-(2\times 10^7)^2=2a(0.019)

16\times 10^{14}-4\times 10^{14}=0.038a

0.038a=12\times 10^{14}

a=\frac{12}{0.038}\times 10^{14}=3.16\times 10^{16}m/s^2

q=1.6\times 10^{-19} C

Mass of electron,m=9.1\times 10^{-31} kg

E=\frac{ma}{q}

Substitute the values

E=\frac{9.1\times 10^{-31}\times 3.16\times 10^{16}}{1.6\times 10^{-19}}

E=1.8\times 105 N/C

7 0
4 years ago
Positive electric charge Q is distributed uniformly throughout the volume of an insulating sphere with radius R.From the express
AlladinOne [14]

Answer:

Vb = k Q / r        r <R

Vb = k q / R³ (R² - r²)    r >R

Explanation:

The electic potential is defined by

             ΔV = - ∫ E .ds

We calculate the potential in the line of the electric pipe, therefore the scalar product reduces the algebraic product

             VB - VA = - ∫ E dr

Let's substitute every equation they give us and we find out

r> R

           Va = - ∫ (k Q / r²) dr

           -Va = - k Q (- 1 / r)

We evaluate with it Va = 0 for r = infinity

          Vb = k Q / r        r <R

         

We perform the calculation of the power with the expression of the electric field that they give us

           Vb = - int (kQ / R3 r) dr

  We integrate and evaluate from the starting point r = R to the final point r <R

         Vb = ∫kq / R³ r dr

         Vb = k q / R³ (R² - r²)

This is the electric field in the whole space, the places of interest are r = 0, r = R and r = infinity

8 0
3 years ago
Jolene travels north 5 miles and then goes west 3 miles before coming straight back south 2 miles. What is her distance
Maurinko [17]

Answer:

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Explanation:

8 0
3 years ago
A certain instant camera determines the distance to the subject by sending out a sound wave and measuring the time needed for th
valentinak56 [21]
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t= \frac{S}{v}= \frac{2L}{v}= \frac{2\cdot 3.42 m}{343 m/s}=0.020 s
6 0
3 years ago
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