cardiovascular endurance :))
 
        
             
        
        
        
Answer:

Explanation:
We are given that 


d=1.9 cm=
Using 1m=100 cm
We have to find the electric field strength.

Using the formula





Mass of electron,m

Substitute the values 


 
        
             
        
        
        
Answer:
Vb = k Q / r        r <R
 Vb = k q / R³ (R² - r²)    r >R
Explanation:
The electic potential is defined by
              ΔV = - ∫ E .ds
We calculate the potential in the line of the electric pipe, therefore the scalar product reduces the algebraic product
              VB - VA = - ∫ E dr
Let's substitute every equation they give us and we find out
r> R
            Va = - ∫ (k Q / r²) dr
            -Va = - k Q (- 1 / r)
We evaluate with it Va = 0 for r = infinity
           Vb = k Q / r        r <R
          
We perform the calculation of the power with the expression of the electric field that they give us
            Vb = - int (kQ / R3 r) dr
   We integrate and evaluate from the starting point r = R to the final point r <R
          Vb = ∫kq / R³ r dr
          Vb = k q / R³ (R² - r²)
This is the electric field in the whole space, the places of interest are r = 0, r = R and r = infinity
 
        
             
        
        
        
The total distance covered by the sound wave is twice the distance between the camera and the subject (because the wave has to reach the subject and then travel back to the camera), so 2L, where L=3.42 m. The speed of sound is v=343 m/s. It is a uniform linear motion, so we can use the basic relationship between space (S), time (t) and velocity (v) to find the time the wave needs to return to the camera:
