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3 years ago

Which object has the most thermal energy?

Physics

2 answers:

o-na [289]3 years ago

8 0

Answer:

10 kg rock at 15 degrees celcius

den301095 [7]3 years ago

3 0

Answer:

D is the answer

Explanation:

D is the most highest one so

the answer is D

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A student is about to sled down a hill. He stands on a hill which is 30 meters tall and he weighs 40kg what is his GPE

PolarNik [594]

Answer:

11760J

Explanation:

Given parameters:

Height of hill = 30m

Weight = 40kg

Unknown:

Gravitational potential energy = ?

Solution:

To find the gravitational potential energy, it is the energy due to the position of a body;

G.PE = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now insert the parameters and solve;

G.PE = 40 x 9.8 x 30 = 11760J

3 0

3 years ago

The driver of a car applies the brakes for 4.0 s.As a result an average force of 7500N is exerted in the car to slow it down.Wha

Sindrei [870]

Answer:

The change in momentum of the car is 30,000 kg m/s

Explanation:

Given,

The force exerted on the car to slow down, F = 7500 N

The time period of force, t = 4 s

The rate of change of momentum of the object is equal to the force acting on it.

Therefore,

Where v and u are the final and initial velocity of the car. The change in momentum of the car,

mv - mu = F x t

= 7500 x 4

= 30,000 kg m/s

Hence the change in momentum of the car is 30,000 kg m/s

7 0

3 years ago

Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too gr

IgorLugansk [536]

(a) 273.9 V

The power rating of the resistor is given by

$P=\frac{V^2}{R}$

where

P is the power rating

V is the potential difference across the resistor

R is the resistance

If the maximum power rating is $P=5.0 W$ , and the resistance of the resistor is $R=15 k\Omega = 15000 \Omega$ , then we can find the maximum potential difference across the resistor by re-arranging the previous equation for V:

$V=\sqrt{PR}=\sqrt{(5.0 W)(15000 \Omega)}=273.9 V$

(b) 1.6 W

In this case, we have:

$R=9.0 k\Omega = 9000 \Omega$ is the resistance of the resistor

$V=120 V$ is the potential difference across the resistor

So we can find the power rating by using the same formula of part (a):

$P=\frac{V^2}{R}=\frac{(120 V)^2}{9000 \Omega}=1.6 W$

(c) Maximum voltage: 14.1 V; Rate of heat: 2.00 W and 3.00 W

Here we have two resistors of

$R_1 = 100 \Omega\\R_2 = 150 \Omega$

and each resistor has a power rating of

P = 2.00 W

So the greatest potential difference allowed in the first resistor is

$V=\sqrt{PR_1}=\sqrt{(2.00 W)(100 \Omega)}=14.1 V$

While the greatest potential difference allowed in the second resistor is

$V=\sqrt{PR_2}=\sqrt{(2.00 W)(150 \Omega)}=17.3 V$

So the greatest potential difference allowed not to overheat either of the resistor is 14.1 V.

In this condition, the power dissipated on the first resistor is 2.00 W, while the power dissipated on the second resistor is

$P_2 = \frac{V^2}{R_2}=\frac{(14.1 V)^2}{150 \Omega}=1.33 W$

And this corresponds to the rate of heat generated in the first resistor (2.00 W) and in the second resistor (1.33 W).

4 0

3 years ago

An electron is moving at a speed of 2.50 ✕ 104 m/s in a circular path of radius of 3.0 cm inside a solenoid. The magnetic field

bogdanovich [222]

Answer:

Explanation: you would need to divide the two numbers

5 0

3 years ago

Calculate the power of a train that uses 2MJ of chemical energy in 4<br> seconds.

nadya68 [22]

Answer:

500 kW

Explanation:

Given that,

Energy of the train, E = 2 MJ = 2×10⁶ J

Time, t = 4 seconds

We need to find the power of the train. We know that,

Power = energy/time

So,

$P=\dfrac{2\times 10^6}{4}\\\\P=500000\ W\\\\or\\\\P=500\ kW$

So, the power of the train is equal to 500 kW.

6 0

3 years ago