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rusak2 [61]
3 years ago
8

A slingshot fi res a pebble from the top of a building at a speed of 14.0 m/s. The building is 31.0 m tall. Ignoring air resista

nce, fi nd the speed with which the pebble strikes the ground when the pebble is fi red (a) horizontally, (b) vertically straight up, and (c) vertically straight down.
Physics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

Explanation:

given,

speed of the pebble = 14 m/s

height of the building = 31 m

ignoring air resistance

a) horizontally

 V_x = 14 m/s

time = \sqrt{\dfrac{2h}{g}}

time = \sqrt{\dfrac{2\times 31}{9.8}}

times  = 2.52 s

v_y = 9.8 x 2.52

v_y = 24.7 m/s

resultant velocity

      = \sqrt{24.7^2+14^2}

      = 28.39 m/s

b) vertically straight up

max height = \dfrac{v^2}{2g}

                   = \dfrac{15^2}{2\times 9.8}

                   = 11.47 m

height covered = 31 + 11.47

                          = 42.47 m

velocity = \sqrt{2gh}

             = \sqrt{2\times 9.8 \times 42.47}

             = 28.85 m/s

c) vertically down

v² = u² + 2as

v² = 2 × 9.8 × 31 +14²

v² = 803.6

v = 28.35 m/s

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A small mailbag is released from a helicopter that is descending steadily at 3 m/s.
mario62 [17]

<u>Answer:</u>

a) Speed of mailbag after 3 seconds = 32.4 m/s

b) Package is 44.1 meter below helicopter

c) If the helicopter was rising steadily at 3.00 m/s

       Speed of mailbag after 3 seconds = 26.4 m/s

       Package is 44.1 meter below helicopter

<u>Explanation:</u>

a)  We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

   Initial velocity = 3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

   v = 3+9.8*3 = 32.4 m/s

  Speed of mailbag after 3 seconds = 32.4 m/s

b) We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Velocity of helicopter = 3 m/s, time taken = 3 seconds, acceleration = 0 m/s^2.

    s= 3*3+\frac{1}{2} *0*3^2\\ \\ s=9m

    Distance traveled by helicopter = 9 meter.

 Velocity of package = 3 m/s, time taken = 3 seconds, acceleration = 9.8 m/s^2.

  s= 3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 53.1m

  Distance traveled by package  = 53.1 meter.

So package is (53.1-9)meter below helicopter = 44.1 m

c) Initial velocity = -3 m/s, acceleration = 9.8 m/s^2 and time = 3 seconds.

  v = -3+9.8*3 = 26.4 m/s

  Speed of mailbag after 3 seconds = 26.4 m/s

 Velocity of helicopter = -3 m/s, time taken = 3 seconds, acceleration = 0 m/s^2.

    s= -3*3+\frac{1}{2} *0*3^2\\ \\ s=-9m

    Distance traveled by helicopter = 9 meter.

 Velocity of package = -3 m/s, time taken = 3 seconds, acceleration = 9.8 m/s^2.

  s= -3*3+\frac{1}{2} *9.8*3^2\\ \\ s= 35.1m

  Distance traveled by package  = 35.1 meter.

So package is (35.1+9)meter below helicopter = 44.1 m

4 0
3 years ago
What does basketballs have inside of it
FrozenT [24]
Hi there!

Great question!

Basketballs have air inside them. A special pump is used to insert the air. That's why you can lift the basketballs off the ground easily. If it was a solid, though, you'd hardly be able to lift the ball up! Basketballs can float, too, because anything with air inside can float. If it were solid, it would sink in the water easily.

Hope this helps! :D
4 0
3 years ago
Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

7 0
3 years ago
A pitcher exerts a force on a baseball that is 30 times the balls weight. How fast is the pitcher accelerating the ball?
iVinArrow [24]

Answer:

 Pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

Explanation:

  Force applied on baseball = 30 times weight of the ball.

   Weight of ball = mg, where m is the mass of ball and g is acceleration due to gravity value.

  We have force applied is also equal to product of mass and acceleration.

                            F = ma = 30 x mg

                                 a = 30g

   So, pitcher is accelerating the ball at 30 times of acceleration due to gravity = 294 m/s²

8 0
3 years ago
What is a real life example of something impermeable? (please help now!!) (due tomorrow!!)
Nutka1998 [239]
Impermeable is a substance that is water proofed e.g glass, aluminium e.t.c <span />
6 0
3 years ago
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