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Usimov [2.4K]
3 years ago
14

Anyways chile , what y’all doing virtual or school ?

Physics
2 answers:
Lady bird [3.3K]3 years ago
8 0
First year of college entirely virtual, r.i.p.
goldenfox [79]3 years ago
3 0

Answer:bggfd

<em>this cow be doing that viurtua</em>Explanation:

sedioisiij

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The box is pushed to the right with a force of 40 Newtons and it just begins to move what is the maximum static frictional force
Vesnalui [34]

Answer:

The maximum static frictional force is 40N.

Explanation:

When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).

This coefficient defines the maximum static friction force that we can have.

So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.

In this case, we know that we apply a force of 40N and the object just starts to move.

Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.

3 0
3 years ago
What is the value of work done on an object when a 70–newton force moves it 9.0 meters in the same direction as the force?
slava [35]

Answer:

630 J

Explanation:

W = Fdcosθ

W = 70(9)cos0

W = 630 J

5 0
3 years ago
Help plz anyone ?????
Alexus [3.1K]

Answer:

Most likely, it will be harder to get strong magnets to change phase because they have more density.

3 0
3 years ago
If the speed of a particle is doubled, what happens to its kinetic energy?
Norma-Jean [14]

Answer:

it increases

Explanation:

maybe for example we have 5pets then you multiple them by two u get 10

4 0
3 years ago
A 1280 kg car is moving 4.92 m/s. a 509 N force then pushes it forward for 28.7 m. what is its final KE?(unit=J)PLEASE HELP
laila [671]

Answer:

The answer to your question is: total energy = 30100.4 J

Explanation:

Kinetic energy (KE) is the energy due to the movement of and object, its units are joules (J)

Data

mass = 1280 kg

speed = 4.92 m/s

Force = 509 N

distance = 28.7 m

Formula

KE = \frac{1}{2} mv^{2}

Work = Fd

Process

- Calculate Kinetic energy

- Calculate work

- Add both results

KE = \frac{1}{2} (1280)(4.92)^{2}

KE = 15492.1 J

Work = (509)(28.7)

Work = 14608.3 J

Total = 15492.1 + 14608.3

Total energy = 30100.4 J        

8 0
3 years ago
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