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wlad13 [49]
3 years ago
6

List four ways you can avoid injury while using HCl and three steps you would take in case of an accidental exposure to HCl need

the answer asap
Chemistry
2 answers:
Lisa [10]3 years ago
7 0
Wear a chemical-resistant apron, chemical-resistant gloves and chemical splash goggles at all times when handling HCl to protect your eyes and skin. Concentrated hydrochloric acid is toxic if inhaled, so avoid breathing it in and always handle it while under a fume hood.
olga_2 [115]3 years ago
7 0

Answer:  

Explanation: Four ways you can avoid injury while using HCl -

a) It's concentrated form is highly toxic so better use in the experiment hood.

b) Don't inhale its fumes.

c) Use lab coat while performing experiments.

d) Protect your eyes by wearing eye glare.

Three steps you would take in case of an accidental exposure to HCl -

a) Inform the lab assistant and teachers regarding the mishap.

b) Don't try to use any kind of ointment or medicated thing on the affected area without any medical advice.

c) You can use sodium bicarbonate to neutralize it.

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Eroded sediments from further upstream clogged Jakarta’s rivers and canals, causing them to overflow. Similar erosion-related floods have occurred in many other countries, such as Colombia, India, the Philippines and Democratic Republic of the Congo.
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Four balloons, each with a mass of 10.0 g, are inflated to a volume of 20.0 L, each with a different gas: helium, neon, carbon m
weeeeeb [17]
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
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3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
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Take the following out of scientific notation 3.74 x 10^7<br> Please help me
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Answer:

37400000000 is the <em>ans</em>

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A more reactive metal displaces a less reactive metal from salt solution. Such reactions are called:
motikmotik

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CO2+2H2O=H3O^++HCO3^-
bekas [8.4K]

<u>Answer:</u>

<em>Bronsted Lowry Theory</em>

<em>CO_2 is the acid </em>

<em>H_2 O is the base </em>

<em>H_3 O^+ is the conjugate acid and </em>

<em>HCO_3^- is the conjugate base</em>

<u>Explanation:</u>

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.  

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.  

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,  

H^++H_2O\Rightarrow H_3O^+

H_3O^+ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example  

Let us consider the example given in the question

CO_2+2H_2 O>H_3 O^+   +HCO_3^- can be written as (removed 1 H_2 O from both the sides )

CO_2+H_2 O>H^++HCO_3^- or  

CO_2+H_2 O  > H_2 CO_3 reversing the equation  

H_2 CO_3+H_2 O>H_3 O^+  +HCO_3^-

H_2 CO_3 is the acid which donates H^+ to form HCO_3^-

H_2 O is the base which gains H^+ to form H_3 O^+

HCO_3^- is the conjugate base and H_3 O^+ is the conjugate acid

So

CO_2 is the acid

H_2 O is the base

H_3 O^+ is the conjugate acid and

HCO_3^- is the conjugate base

(Answer)  

5 0
3 years ago
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