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Serhud [2]
3 years ago
9

What is the difference between current electricity and static electricity

Physics
2 answers:
Allisa [31]3 years ago
7 0

Answer:

The most significant difference between the static and current electricity is that in static electricity the charges are at rest and they are accumulating on the surface of the insulator. Whereas in current electricity the electrons are moving inside the conductor.

Mama L [17]3 years ago
3 0

Answer:

Static electricity is electricity that does not flow. It is produced by electrons rubbing off one object and being collected on another. It cannot flow through a wire like the electricity in your home. An example of static electricity is rubbing your hair on a balloon. static electricity causes your hair to stick up. On the other hand, current electricity can flow. It is generated by batteries and power plants. In current electricity the electrons are moving inside the conductor. Current electricity runs through circuits. These circuits run all around your homes. Current electricity is also what we use in our homes. An example of current electricity is the electricity that we use from outlets.

Explanation:

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The mechanical energy of a coconut falling from a tree______
Alexxandr [17]

Answer:

D. is the answer

Explanation:

8 0
3 years ago
Read 2 more answers
One horsepower (hp) is the amount of power required to lift a 75-kg mass a vertical distance of 1 m in 1 s. What is 2 hp equival
Vladimir [108]

Answer:

1470 W

Explanation:

Power: This can be defined as the rate at which work is done or energy is used up. The S.I unit of power is Watt (W).

The expression for power is given as,

P = Energy/time

P = mgh/t ...................... Equation 1

Where P = power, m = mass, h = height, t = time, g = acceleration due to gravity.

Given: m = 75 kg, g =9.8 m/s², h = 1 m, t = 1 s.

Substitute into equation 1

P = (75×1×9.8)/1

P = 735 W.

From the above,

1 hp = 735 W

2 hp = (2×735) W

2 hp = 1470 W.

Hence 2 hp = 1470 W

8 0
3 years ago
Starting at the same time, an arrow and a ball are shot horizontally with a speeds of 50 m/s and 44 m/s respectively from the to
Yuri [45]

Answer:

option D

Explanation:

given.

horizontal velocity of arrow and a ball given as  50 m/s and 44 m/s respectively from the top of a building over flat ground.

In vertical direction, they are both identical

In vertical direction the initial velocity of arrow and a ball  is 0  m/s

Their acceleration due to gravity  is same for both arrow and a ball  9.8 m/s²

they will react bottom at the same time

 time of flight is same for both

now,

In horizontal direction,

distance = speed × time

Since speed is more for arrow, it will travel more horizontal distance  at the same time.

the correct answer is option D

5 0
3 years ago
In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met
mixer [17]

Answer:

The kinetic energy of the ejected electrons increases.

Explanation:

As we know that electrons are only ejected from a metal surface if the frequency of the incident light increases the work function of the metal. If the frequency of the incident light is less than the work function of the metal no matter how intense the beam the electrons will not be ejected from the surface.

Using conservation of energy principle we have

E_{incident}=h\nu +\frac{1}{2}mv^{2}

If we increase the intensity  of incident light the term on the LHS of the above equation increases this increase appears in the kinetic energy term in RHS of the equation since h\times \nu remains constant.

5 0
4 years ago
Read 2 more answers
As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the ave
DedPeter [7]

Answer:

-29.2\times 10^{3} N

Explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time=\Delta t=1.3 s

We have to find the average force exerted on the car.

Average force=\frac{change\;in\;momentum}{\Delta t}

F_{avg}=\frac{mv-mu}{1.3}

F_{avg}=\frac{1900(0)-1900(20)}{1.3}

F_{avg}=\frac{-38000}{1.3}=-29.2\times 10^{3} N

Hence, the average force exerted on the car that hits a line of water barrels=-29.2\times 10^{3} N

8 0
3 years ago
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