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Strike441 [17]
3 years ago
15

I need help. Like, I really dont know!!!

Chemistry
2 answers:
kap26 [50]3 years ago
7 0

Answer:

GIve me insta

Explanation:

zavuch27 [327]3 years ago
3 0

Answer: Ooo you be looking like a snack :D

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How does the appearance of a substance change when it<br> changes phase?
kicyunya [14]

Answer:

Melting: the substance changes back from the solid to the liquid. Condensation: the substance changes from a gas to a liquid. Vaporization: the substance changes from a liquid to a gas. Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase.

Explanation:

6 0
3 years ago
What is state symbols
Ganezh [65]

Answer:

Explanation:

State symbols are used in chemical equations to delineate the state of matter in which the reaction is taking place.

They give a good perspective of the state of the reactants and products obtainable.

There are basically four states of matter in every chemical reaction:

  • Solids are symbolized by small letter (s)
  • Liquids are represented by (l)
  • Gases are shown by (g)
  • Aqueous solutions having water as the medium by (aq)

These symbols appear as subscript in front of the chemical species.

5 0
2 years ago
How to atoms form a new substance
marin [14]

Answer:

they join together

Explanation:

6 0
2 years ago
Read 2 more answers
Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
3 years ago
An increase in temperature results in A) a decrease in the required activation energy while the reaction rate remains constant.
N76 [4]

Answer:

C) an increase in rate of reaction because reactant molecules collide with greater energy

Explanation:

Temperature is one of the factors that affect the rate of a reaction. The rate of a reaction increases with an increase in temperature and vice versa. When the temperature of a reaction increases, the kinetic energy of the reactant molecules increases causing them to react at a faster rate.

The reactant molecules respond to an increase in temperature by colliding at a faster rate due to an increased kinetic energy between the reactant molecules.

7 0
3 years ago
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