Answer:
(a)
4) The magnitude of buoyancy force is equal to that of ball's weight
(b) The magnitude of buoyancy force is larger than that of ball's weight. The tension on second ball is 158 newtons
(c) The magnitude of buoyancy force is larger than that of ball's weight. The tension on third ball is 218 newtons.
Explanation:
Newton's third law of motion states that forces always occurs in pairs. For every reaction there is an equal an opposite reaction. For Ball 1 the magnitude of buoyancy force is equal to that of ball's weight. Buoyancy force works against the gravity. Ball 2 and ball 3 have same buoyancy force. The buoyancy force for ball 2 and ball 3 is larger than that of ball's weight.
Tension = Wb - fb
Tension for Ball 2 = 1000 - 842 = 158 newtons
Tension for Ball 3 = 1000 - 1218 = -218 newtons
The second diver have to leap to make a competitive splash by 4.08 m high.
<h3>What is potential energy?</h3>
The energy by virtue of its position is called the potential energy.
PE = mgh
where, g = 9.81 m/s²
Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.
The potential energy of the first diver must be equal to the second diver.
P.E₁ = P.E₂
m₁gh₁ = m₂gh₂
Substitute the vales, we have
136 x 3 = 100 x h₂
h₂ = ₂4.08 m
Thus, the second diver need to leap by 4.08 m high.
Learn more about potential energy.
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B, this is because the particles in a solid such as the diamond can not move and even though they are locked into place they still vibrate
Hi there! :)
Reference the diagram below for clarification.
1.
We must begin by knowing the following rules for resistors in series and parallel.
In series:
In parallel:
We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.
Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
2.
We can use Ohm's law to solve for the current in the circuit.
3.
For resistors in series, both resistors receive the SAME current.
Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.
In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.
4.
Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.
