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Rama09 [41]
3 years ago
11

90 POINTS!!!!!

Physics
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer:

-696 N

1440 N

Explanation:

The force that the car exerts on the trailer is:

T = m₂ a

T = (580 kg) (1.20 m/s²)

T = 696 N

The force that the trailer exerts on the car is opposite and equal.

T' = -T

T' = -696 N

The net force on the car is:

∑F = m₁ a

∑F = (1200 kg) (1.20 m/s²)

∑F = 1440 N

attashe74 [19]3 years ago
5 0

Answer:

1. What force does the trailer exert on the car? = 696 Newtons

2. -696 Newtons are acting on the car.

Explanation:

1.Calculate the force exerted by the car on the trailer.  

The expression for the force from Newton’s second law is, F=ma

Substitute 580kg for m and 1.2m^2

F=(580kg)(1.20m/s^2  = 696N

2. According to Newton’s third law, an equal force is exerted by the trailer in the opposite direction. Hence, the magnitude of the force is negative.

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Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc
kaheart [24]

Answer:

The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

Explanation:

Given that,

Beat frequency f = 5.0 Hz

Frequency f'= 462 Hz

We need to calculate the possible frequencies for the A string of the other violinist

Using formula of frequency

f'=f_{1}-f...(I)

f'=f_{1}+f...(II)

Where, f= beat frequency

f₁ = frequency

Put the value in both equations

f'=462-5=457\ Hz

f'=462+5=467\ Hz

Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.

4 0
3 years ago
A motorcycle and a police car are moving toward one another. The police car emits sound with a frequency of 523 Hz and has a spe
Firdavs [7]

To solve this problem it is necessary to apply the concepts related to Dopler's Law. Dopler describes the change in frequency of a wave in relation to that of an observer who is in motion relative to the Source of the Wave.

It can be described as

f = \frac{c\pm v_r}{c\pm v_s}f_0

c = Propagation speed of waves in the medium

v_r= Speed of the receiver relative to the medium

v_s= Speed of the source relative to the medium

f_0 =Frequency emited by the source

The sign depends on whether the receiver or the source approach or move away from each other.

Our values are given by,

v_s = 32.2m/s \rightarrow Velocity of car

v_r = 14.8 m/s \rightarrow velocity of motor

c = 343m/s \rightarrow Velocity of sound

f_0 = 523Hz \rightarrowFrequency emited by the source

Replacing we have that

f = \frac{c + v_r}{c - v_s}f_0

f = \frac{343 + 14.8}{343 - 32}(523)

f = 601.7Hz

Therefore the frequency that hear the motorcyclist is 601.7Hz

8 0
4 years ago
1000 kg has 50, 000 joules of kinetic energy. what is it's speed?
kicyunya [14]
The answer is 36 kilometers per hour, or 10 meters per second.
7 0
3 years ago
A particle with charge q = 10-9 C and mass m = 5.0 x 10-9 kg is moving in a magnetic field whose magnitude is 0.003 T. The speed
Marina86 [1]

Answer:

a=0.212 m/s²

Explanation:

Given that

q= 10⁻⁹ C

m = 5 x 10⁻⁹ kg

Magnetic filed ,B= 0.003 T

Speed ,V= 500 m/s

θ= 45°

Lets take acceleration of the mass is a m/s²

The force on the charge due to magnetic filed B

F= q V B sinθ

Also F= m a  ( from Newton's law)

By balancing these above two forces

m a= q V B sinθ

a=\dfrac{qVB\ sin\theta}{m}

a=\dfrac{10^{-9}\times 500\times 0.003\times\ sin45^{\circ}}{5\times 10^{-9}}\ m/s^2

a=\dfrac{10^{-9}\times 500\times 0.003\times\dfrac{1}{\sqrt2}}{5\times 10^{-9}}\ m/s^2

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4 0
4 years ago
We are usually not aware of the electric force acting between two everyday objects because
tatuchka [14]

Answer:We are usually not aware of the electric force acting between two everyday objects because most everyday objects have as many plus charges as minus charges. Option A

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3 0
3 years ago
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