Cu = 63.546
N= 14.001 g/mol
O= 15.999 g/mol * 3 = 47.997
Copper (II) Nitrate has a MW of 125.544 g/mol
6.25 x 125.544
= 784.65 <--- is your answer, if there were was a multiple choice or not :)
Answer:
34.8 mL
Explanation:
First we <u>convert 5.48 g of CuNO₃ into moles</u>, using its<em> molar mass</em>:
- 5.48 g CuNO₃ ÷ 187.56 g/mol = 0.0292 mol
Now we can <u>calculate the volume of the solution</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- 0.840 M = 0.0292 mol / liters
Finally we <u>convert L into mL</u>:
- 0.0348 L * 1000 = 34.8 mL
Answer:
Al₄O₅
Explanation:
The key at the bottom tells us the blue spheres are oxygen atoms and the red spheres are aluminum atoms. By counting, there are 4 aluminum atoms and 5 oxygen atoms. Therefore, the formula is Al₄O₅.
Answer:
-0.85KJ
Explanation:
Given N2(g) + H2(g) <--->2NH3(g)
Kp =[ P(NH3)]²/[P(H2)]³[P(N2)]
Where P is the pressure of the gas
P(H2)b= P(N2) = 125atm
P(NH3) = 200atm
Kp = 2²/(125)³(125)
Kp = 2.048 ×10^-6
∆G = -RTlnKp
R =0.008314 J/Kmol
T = 25 +273/= 298k
= 8.314 ×10^-3 × 298 × ln(2.048 ×10^-6)
= -0.008314 × 298 × (-13.099)
= 32.45KJ
∆G = ∆G° + RTlnKp
∆G = -33.3 + 32.45
∆G = -0.85KJ or -850J
