Answer:
The height to which the ball flies is 86.6 m.
Explanation:
Given that,
Time = 2.05 sec
Acceleration = 9.8 m/s²
We need to calculate the initial velocity of volleyball
Using equation of motion

Where, u = initial velocity
a = acceleration
t = time
Put the value into the formula


We need to calculate the height of the the ball
Using equation of motion

Put the value into the formula



Hence, The height to which the ball flies is 86.6 m.
Answer:
a) the correct answer is 1
, b) x=0 F=0, a=0
x= 0.050 F= -7.5 N, a= -15 m/s²
x= 0.150 F= 22.5 N, a=- 45 m/s²
Explanation:
a) In a mass - spring system the force is given by the Hooke force,
F = - k x
Analyzing this equation we see that the outside is proportional to the elongation from the equilibrium position, therefore the force is zero when the spring is in its equilibrium position
the correct answer is 1
b) we assume that the given values are from the equilibrium position of the spring.
Let's calculate the force
x = 0
F = 0
x = 0.050
F = - 150 0.050
F = - 7.50 N
x = 0.150
F = - 150 0.150
F = - 22.5 N
let's use Newton's second law to find the acceleration
F = m a
a = F / m
x = 0 m
a = 0
x = 0.050 m
a = -7.50 / 0.50
a = - 15 m / s²
x = 0.150 m
a = - 22.5 / 0.50
a = - 45 m/s²
TRASLATE
a) En un sistema masa – resorte la fuerza es dada por la fuerza de Hoke,
F= - k x
analizando esta ecuación vemos que la fuera es proporcional a la elongación desde la posición de equilibrio, por lo tanto la fuerza es cero cuando el resorte esta en su posición de equilibrio
la respuesta correcta es 1
b)suponemos que los valores dados son desde la posición de equilibrio del resorte.
Calculemos la fuerza
x=0
F= 0
x=0.050
F = - 150 0.050
F= - 7.50 N
x= 0.150
F= - 150 0.150
F= - 22.5 N
usemos la segunda ley de Newton para encontrar la aceleración
F = m a
a = F/m
x =0 m
a = 0
x= 0.050 m
a = -7.50/ 0.50
a =- 15 m/s²
x= 0.150 m
a= - 22.5 / 0.50
a= - 45 m/s²
<span>Answer:
For Lewis theory, the most stable species will have a complete octet for as many atoms as possible. Construct Lewis dot structures for each species. You should see that CN+ cannot give a complete octet to the C atom unless a quadruple bond - unknown except in transition metals - is formed. CN will have an odd number of electrons, and is thus a free radical and unstable with respect to dimerization (it forms cyanogen). CN-, the familiar cyanide ion, gives both C and N a complete octet with a triple bond, and is thus the most stable.
Molecular orbital theory is a bit more complex. Nitrogen and carbon are close enough in electronegativity, so the orbitals from the C atom will mix with the same orbitals from the N atom. The molecular orbitals formed will be sigma2s, sigma*2s, pi2p, sigma2p, pi*2p, and sigma*2p. The * denotes an antibonding orbital; these are higher in energy, and electrons placed into these orbitals weaken the bonding between two atoms. CN+ will completely fill the sigma2s, sigma*2s, and pi2p orbitals. CN will add an electron in the bonding sigma2p orbital, and the atoms are thus more strongly bonded than in CN+. CN- fills the sigma2p orbital, and the addition of another bonding electron means that this species has the strongest bond of the three. I might have the names of some of the filled levels incorrect; the energy levels of the sigma2p and pi2p swap at some point. This concept is hard to explain without a picture; see the link.
Thus, both MO and Lewis theory predict CN- as the most stable species, a prediction that matches well with experimental data.</span>
<h2>
Answer: 34.78 m/s</h2>
Explanation:
The momentum
is given by the following equation:
(1)
Where:
is the mass of the object
is the velocity of the object
Finding the velocity from (1):
(2)
<u>Finally:</u>
>>>This is the velocity of the object
Answer:
v=3.66,h-3.66
Explanation:
vertical = 10sin60 - 10sin 30
horizontal =10cos60 + 10cos 30
v = 10×0.8660-10×0.5
h = 10×0.5 + 10 × 0.8660
v=8.660-5.0 = 3.66
h= 5.0-8.660 = -3.66