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irina [24]
4 years ago
7

A parachute on a racing dragster opens and changes the speed of the car from 85 m/sec to 45 m/sec in a period of 4.5 seconds. Wh

at is the acceleration of the dragster?
Physics
1 answer:
Serggg [28]4 years ago
6 0
Acceleration is change is velocity over time. So the change in velocity is 40 and time is 4.5 sec. So the acceleration is 40/4.5=8.89 m/s^2
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Two devices with capacitances of 25 μf and 5.0 μf are each charged with separate 120 v power supplies. calculate the total energ
mash [69]
The energy stored in a capacitor is given by
U= \frac{1}{2} CV^2
where C is the value of the capacitance while V is the voltage difference applied to the capacitor.

Let's calculate the energy of the first capacitor:
U_1 =  \frac{1}{2} (25\cdot 10^{-6}F)(120 V)=1.5 \cdot 10^{-3}J

And now the energy of the second capacitor:
U_2 =  \frac{1}{2} (5 \cdot 10^{-6}F)(120 V)=3 \cdot 10^{-4}J

So, the total energy stored in the two capacitors is
U=U_1 +U_2 = 1.8 \cdot 10^{-3}J
3 0
3 years ago
Read 2 more answers
Potential energy can be converted into kinetic energy, a good example of this is when a pole-vaulter bends the pole during a lea
lesantik [10]

Answer:

The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.

Question:

Why did you lie about being in college?

6 0
3 years ago
Read 2 more answers
You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo
S_A_V [24]

Answer:

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

Z=\sqrt{R^2+\omega^2L^2}       (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

I=\frac{V}{Z}                     (2)

V: voltage amplitude = 30.0V

I=\frac{30.0V}{185.87\Omega}=0.16A

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV            (3)

D. The voltage across the inductor is:

V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V

E. The phase difference is given by:

\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°

5 0
3 years ago
Light of wavelength 480 nm illuminates a pair of slits separated by 0.27 mm. If a screen is place 1.7 m from the slits, determin
Dahasolnce [82]

Answer:

  Δy = 6.05 mm

Explanation:

The double slit phenomenon is described by the expression

      d sin θ = m λ                constructive interference

      d sin θ = (m + ½) λ       destructive interference

      m = 0,±1, ±2, ...

As they tell us that they measure the dark stripes, we are in a case of destructive interference, let's use trigonometry to find the sins tea

      tan θ = y / x

      y = x tan θ

In the interference experiments the measured angle is very small so we can approximate the tangent

      tan θ = sin θ / cos θ

     cos θ = 1

     tan θ = sin θ

     y = x sin θ

We substitute in the destructive interference equation

     d (y / x) = (m + ½) λ

    y = (m + ½) λ x / d

The first dark strip occurs for m = 0 and the third dark strip for m = 2. Let's find the distance for these and subtract it

 m = 0

      y₀ = (0+ ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

      y₀ = 1.511 10⁻³ m

 m = 2

     y₂ = (2 + ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

     y₂ = 7.556 10⁻³ m

The separation between these strips is Δy

     Δy = y₂-y₀

     Δy = (7.556 - 1.511) 10⁻³

     Δy = 6.045 10⁻³ m

     Δy = 6.05 mm

5 0
3 years ago
Which of the following elements is the most chemically reactive?
ivolga24 [154]

Answer:

B) Fluorine

Explanation:

The most reactive element is fluorine, the first element in the halogen group. The most reactive metal is francium, the last alkali metal (and most expensive element).

6 0
3 years ago
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