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3 years ago

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A parachute on a racing dragster opens and changes the speed of the car from 85 m/sec to 45 m/sec in a period of 4.5 seconds. Wh

at is the acceleration of the dragster?

1 answer:

Serggg [28]3 years ago

6 0

Acceleration is change is velocity over time. So the change in velocity is 40 and time is 4.5 sec. So the acceleration is 40/4.5=8.89 m/s^2

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My buddy and I have just finished a dive to 15 metres/50 feet for 60 minutes. We want to return to the same site and depth and s

marishachu [46]

Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

7 0

3 years ago

Which of these planets is the odd one out based on their physical features?

Maurinko [17]

Answer:

mars

Explanation:

the planet that is the odd is Mars

7 0

3 years ago

HELP!!! 30 POINTS+BRAINLIEST!!!!!QUICK!!

tia_tia [17]

Answer:

A:7.2 $ms^{-1}$

B:14.25 $ms^{-1}$

C:1.45 $sec$

D:10.3 $m$

E:2.9 $sec$

F:20.88 $m$

Explanation:

Let $v$ be the velocity and $\alpha$ be the angle between the velocity and ground.

Question A:

Horizontal component of velocity is given by $vcos(\alpha )$ .

So,horizontal component is $16\times cos(63)=16\times 0.45=7.2ms^{-1}$

Question B:

Vertical component of velocity is given by $vsin(\alpha )$ .

So,vertical component is $16\times sin(63)=16\times 0.89=14.25ms^{-1}$

Question C:

Time required is given by $\frac{\text{vertical component of velocity}}{g}}=\frac{14.25}{9.8}=1.45 seconds$

Question D:

Maximum height is given by $\frac{\text{vertical component of velocity}^{2}}{2g}}=\frac{203.06}{19.6}=10.3m$

Question E:

Time of flight is twice the time required to reach maximum height= $2\times 1.45=2.9 seconds$ .

Question F:

The distance between the player and ball after landing is called range and is given by $\text{horizontal component of velocity}\times \text{time of flight}=$ $7.2\times 2.9=20.88m$

8 0

3 years ago

How much heat is released as a 5.89 kg block of aluminum cools from 462 °C to 315 °C. The specific heat capacity of aluminum is

aliina [53]

779,247 J is the amount of heat released.

<u>Explanation:</u>

The equation that gives the amount of heat supplied is

$E \text { or } Q=m \times c_{A l} \times \Delta T$

Where,

E or Q – amount of heat supplied

m- mass

$c_{A l}$ - specific heat capacity of Aluminium

$\Delta T$ – temperature variation caused by heat change

The amount of heat energies that causes the temperature to vary $1^{\circ} \mathrm{C}$ or 1 K per kg of the material is known as specific heat capacity (c)

Here, Given data:

$c_{A l}$ – 0.900 J/g.K

To convert gram into kilogram, multiply and divide by $10^{3}$ , we get

Specific heat capacity of aluminum = 900 J/kg. K

m – 5.89 kg

$\Delta T=462^{\circ}-315^{\circ}=147^{\circ} \mathrm{C}$

By substituting the known values in the above equation, we get

$E \text { or } Q=5.89 \times 900 \times 147=779,247 \mathrm{J}$

5 0

3 years ago

Read 2 more answers

A river flowing steadily at a rate of 240 m3/s is considered for hydroelectric power generation. It is determined that a dam can

Rudiy27

Answer:

power generated = 117.72 MW

Explanation:

given data

flow rate of river = 240 m³/s

height above the surface lake = 50m

solution

we get power generated that is express as

power generated = distance × acceleration due to gravity × elevation head × density of water ......1

power generated = 240 × 9.81 × 50 × 1000

power generated = 117.72 MW

6 0

3 years ago