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sergeinik [125]
3 years ago
7

Calculate the angle of incidence of light ray incident on surface

Physics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

from \: snell {}^{.} s \: law : \\  n =  \frac{ \sin(i) }{ \sin(r) }  \\  \sqrt{3}  =  \frac{ \sin(i) }{ \sin(30 \degree) }  \\  \sin(i)  =  \sqrt{3}  \times  \sin(30 \degree)  \\  \sin(i)  = 0.866 \\ i =  { \sin}^{ -1 } (0.866) \\ i = 60 \degree

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In which of the following elevator situations would the acceleration be positive. Select TWO answers
kap26 [50]

Both options 5 and 6

Explanation:

Let us consider option 5,

In option 5 body is moving up with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

Let us consider option 6,

In option 6 body is moving down with initial velocity lower than that of final velocity which gets accelerated. Therefore the acceleration is positive in this case.

4 0
3 years ago
Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

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3 0
3 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

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Given that,

Net force acting on the car, F = -8750 N

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Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
The resistance is 5 Ω and the amount of electric current is 2 A. This means that the amount of voltage is
Hatshy [7]

Answer:

I=2A

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formula

V=IR

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