Answer:
16∠45° Ω
Explanation:
Applying,
Z = V/I................... Equation 1
Where Z = Impedance, V = Voltage output, I = current input.
Given: V = 120cos(10t+75°), = 120∠75°, I = 7.5cos(10t+30) = 7.5∠30°
Substitute these values into equation 1
Z = 120cos(10t+75°)/7.5cos(10t+30)
Z = 120∠75°/ 7.5∠30°
Z = 16∠(75°-30)
Z = 16∠45° Ω
Hence the impedance of the linear network is 16∠45° Ω
Answer:
9.38 m/s
Explanation:
Mass is conserved.
m₁ = m₂
ρ₁ Q₁ = ρ₂ Q₂
Assuming no change in density:
Q₁ = Q₂
v₁ A₁ = v₂ A₂
v₁ π r₁² = v₂ π r₂²
v₁ r₁² = v₂ r₂²
Plugging in values:
(1.50 m/s) (0.0250 m)² = v (0.0100 m)²
v = 9.38 m/s
Chemical=B
Mechanical=C
Nuclear=A
Electromagnetic=D
Thermal=E
I think these are right but if not I’m sorry
Hope I helped :]
Answer:
Going from earth to the sun a probe would encounter the next layers in order:
- Corona
- Transition Region
- Chromosphere
- Photosphere
- Convection Zone
- Radiative Zone
- Core
A brief description of them:
Corona is the outermost layer and it cannot be seen with the naked eye, is starts at about 2100 km from the surface of the sun and it has no limit defined.
Transition Region is between the corona and the chromosphere, it has an extension of about 100km
The chromosphere is between 400 km from the surface of the sun to 2100 km. In this layer the further you get away from the sun it gets hotter.
The photosphere is the surface of the sun, the part that we can see, and extends from the surface to 400km.
The convection zone is where convection happens, hot gas rises, cools and rises again.
Radiative Zone is where the photons try to rise to move to higher layers.
The core of the Sun is where nuclear fusion occurs due to the very high temperatures.
This would be an example of active immunity
