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3 years ago

Imagine the running deer has a mass of 100 kg and is running at a speed of 8 m/s. What is the deer’s kinetic energy, in joules?

Physics

1 answer:

stiv31 [10]3 years ago

3 0

Answer: 3200 joules.

Explanation:

Mass of deer = 100kg

Speed of running deer = 8 m/s

Kinetic energy = ?

Kinetic energy is the energy possessed by a moving body (deer). It is measured in joules.

Thus, Kinetic energy = 1/2 x (Mass x velocity^2)

K.E = 1/2 x (100kg x (8m/s)^2)

K.E = 1/2 x (100 x 64)

= 0.5 x 6400

= 3200 joules

Thus, the kinetic energy of the running deer is 3200 joules.

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In a Compton scattering experiment, scattered photon is found to have its wavelength three times of the incident photon for the

Svetlanka [38]

Answer:

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4 years ago

A steel plate weighing 180 lb with center of gravity at point G is supported by a roller at point A, a bar DE, and a horizontal

melamori03 [73]

Answer:

Therefore, the force supported by the hydraulic cylinder is = -70.01 lb

Thus, the force supported by the bar = -233.84 lb

The reaction force supported by the reaction of the roller = 341.31 lb

Explanation:

The attached diagrams is shown in the file below:

From there; taking moments about point A

$\sum M__A }=0$

- 40 (180) - (80) $F_E$ Cos 37° + 55

-7200 + $F_E$ (-80 Cos 37° + 55 sin 37° ) = 0

= - 7200 - 30.79 $F_E$

- 30.79 $F_E$ = 7200

$F_E$ = $-\frac{7200}{30.79}$

$F_E$ = -233.84 lb

Thus, the force supported by the bar = -233.84 lb

Taking the equilibrium of forces in the vertical direction

$\sum f_y = 0$

$F_E$ sin 37 + $F_A$ cos 20 - $F_G$ = 0

- 233.84 sin 37 + $F_A$ cos 20 - 180 = 0

$F_A$ cos 20 = 320.73

$F_A$ = $\frac{320.73}{cos 20}$

$F_A$ = 341.31 lb

The reaction force supported by the reaction of the roller = 341.31 lb

Taking the equilibrium of forces on the horizontal direction.

$\sum f_y = 0$

$F_E$ cos 37 - $F_{CB} + F_A$ sin 20° = 0

-233.84 cos 37 - $F_{CB}$ + 341.31 sin 20° = 0

-186.75 - $F_{CB}$ + 116.74 = 0

- $F_{CB}$ -70.01 = 0

- $F_{CB}$ = 70.01

$F_{CB}$ = - 70.01 lb

Therefore, the force supported by the hydraulic cylinder is = -70.01 lb

7 0

4 years ago

CAN ANYONE HELP PLEASE I NEED THIS DONE BY TODAY!! I WILL MARK YOU BRIANLYIST.

bulgar [2K]

I have no idea my dude sorry

7 0

3 years ago

A cardinal (Richmondena cardinalis) of mass 3.70×10−2 kg and a baseball of mass 0.144 kg have the same kinetic energy. What is t

Radda [10]

Answer:

$\frac{p_{c}}{p_{b}}\approx 0.507$

Explanation:

Since the cardinal and ball have the same kinetic energy, it is possible to determine the ratio between speeds. (c for cardinal, b for baseball)

$K_{c} = K_{b}$

$\frac{1}{2}\cdot m_{c}\cdot v_{c}^{2}= \frac{1}{2}\cdot m_{b}\cdot v_{b}^{2}$

$\frac{v_{c}}{v_{b}}=\sqrt{\frac{m_{b}}{m_{c}} }$

The ratio is obtained by multiplying each side by $\frac{m_{c}}{m_{b}}$ :

$\frac{p_{c}}{p_{b}}=\frac{m_{c}}{m_{b}}\cdot \sqrt{\frac{m_{b}}{m_{c}} }$

$\frac{p_{c}}{p_{b}}= \sqrt{\frac{m_{c}}{m_{b}} }$

The value of this ratio is:

$\frac{p_{c}}{p_{b}}\approx 0.507$

3 0

4 years ago

Read 2 more answers

What necessary information is missing from this formula page? W-work F-force x-distance Work = force(distance) W = Fx a. Formula

Nataliya [291]

Answer:

it should be Work = F * d * cos(theta)

Explanation:

Force is mass * acceleration, and displacement is the distance between the starting and ending point.

we need theta because it can be used to calculate work when going up an incline surface. And we tend to use cosine because we are assuming that our motion is primarily in the X direction.

5 0

3 years ago