Answer:
Step-by-step explanation:
2 = ⅔[6] + b
4
If you want it in <em>Standard Form</em>:
y = ⅔x - 2
- ⅔x - ⅔x
_________
−⅔x + y = −2 [We do not want fractions in our standard equation, so multiply by the denominator to get rid it.]
−3[−⅔x + y = −2]
_______________________________________________
−5 = 3⁄2[10] + b
15
If you want it in <em>Standard</em><em> </em><em>Form</em>:
y = 3⁄2x - 20
- 3⁄2x - 3⁄2x
__________
−3⁄2x + y = −20 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]
−2[−3⁄2x + y = −20]
* Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so ⅔ and 3⁄2 remain the way they are.
I am joyous to assist you anytime.
Answer:
A. 50.24
Step-by-step explanation:
<em><u>It is given that "r," represents the radius, and it's also given that it's 4. All you need to do is plug in 4 for r, into the function, like so:</u></em>
<em><u /></em>
f(4) = 3.14(16)
f(4) = 50. 24
Step-by-step explanation:
Given:
This field will have a scalar potential if it satisfies the condition . While the first x- and y- components of are satisfied, the z-component doesn't.
Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector as
and its differential is
The work done then is given by
If I'm thinking correct it would say 5 120. HOPE I HELPED>
Find slope as negative reciprocal of 2 => m=-1/2
y=mx + b
8=5(-1/2) +b
b=21/2
y= -1/2x +21/2