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aev [14]
3 years ago
7

Suppose that you arrive at a bus stop​ randomly, so all arrival times are equally likely. The bus arrives regularly every 90 min

utes without delay. What is the expected value of your waiting​ time?
Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

"Expected value of your waiting time would be 45"

Step-by-step explanation:

Since you arrive randomly and all arrival times are equally likely, half the time you will arrive at the bus stop during the 90/2=45 minute period after the last bus left, and half the time you'll arrive during the 15 minute period before the next bus arrives.

In general, you'll arrive at the bus stop n < 45 minutes AFTER the last bus left and as often as you'll arrive at the bus stop n < 45 minutes BEFORE the next bus comes The average of those times, if we calculate, will be 45.

Hence, your average waiting time can be 45 and this means the "expected" value of your waiting time.

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Find the distance between −340 and 207 on the number line.
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Answer:

547

Step-by-step explanation:

To find the difference between the 2 numbers, subtract -340 from 207:

207 - (-340)

Subtracting a negative number will change to adding a positive number:

207 + 340

= 547

So, the distance is 547

7 0
3 years ago
I will give brainiest to whoever answers correctly !!
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I don’t know if this is the right answer

700*.075 ÷ 24 will give you your monthly payment.

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Amy and her sister are making lemonade for the school dance. Their recipe makes 2 quarts of lemonade. If they make 35 times the
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3 years ago
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A survey was done that asked people to indicate whether they preferred to swim in a pool or in an ocean. The results are shown i
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Given:
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Age 30 and younger             228                         54                 282
Over 30 years old                142                        185                 327
total                                    370                        239                609

Frequencies:
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Age 30 and younger     228/609 = 0.37         54/609 = 0.09       282/609 = 0.46
Over 30 years old        142/609 = 0.23       185/609 = 0.30       327/609 = 0.54
<span>total                           370/609 = 0.61       239/609 = 0.39       609/609 = 1.00</span>

<span>The relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean is 0.30</span>    
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Answer:

11

Step-by-step explanation:

because that are 11 pencils that are 6 inches or longer, that's what the picture says.

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