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fomenos
3 years ago
10

How many exercises are there? ​

Physics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer:

There are 4 exresise ;endurance, strength, balance, and flexibility. Each one has different benefits.

Explanation:

Endurance activities, often referred to as aerobic, increase your breathing and heart rates.

Your muscular strength can make a big difference. Strong muscles help you stay independent and make everyday activities feel easier, like getting up from a chair, climbing stairs, and carrying groceries.

Balance exercises help prevent falls, a common problem in older adults that can have serious consequences.

Stretching can improve your flexibility. Moving more freely will make it easier for you to reach down to tie your shoes or look over your shoulder when you back your car out of the driveway.

hope this can help you...

aivan3 [116]3 years ago
4 0
There are 4 exercises! I hope this helps :)
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Humans have 46 chromosomes. The cells created by meiosis have
alukav5142 [94]
Meiosis creates the gamete cells, because these cells are used in reproduction they only have 26 chromosomes two of these cells join together to make a full 46 chromosomes.

Hope this helps! :)
7 0
3 years ago
1. A racing car with the driver weighs 1825 lb. Find the kinetic energy in ft*lb when traveling with a speed of 100 mi/hr.
Svetlanka [38]

Answer:

1. 610,000 lb ft

2. 490 J

Explanation:

1. First, convert mi/hr to ft/s:

100 mi/hr × (5280 ft / mi) × (1 hr / 3600 s) = 146.67 ft/s

Now find the kinetic energy:

KE = ½ mv²

KE = ½ (1825 lb / 32.2 ft/s²) (146.67 ft/s)²

KE = 610,000 lb ft

2. KE = ½ mv²

KE = ½ (5 kg) (14 m/s)²

KE = 490 J

6 0
4 years ago
A +71 nC charge is positioned 1.9 m from a +42 nC charge. What is the magnitude of the electric field at the midpoint of these c
viva [34]

Answer:

The net Electric field at the mid point is 289.19 N/C

Given:

Q = + 71 nC = 71\times 10^{- 9} C

Q' = + 42 nC = 42\times 10^{- 9} C

Separation distance, d = 1.9 m

Solution:

To find the magnitude of electric field at the mid point,

Electric field at the mid-point due to charge Q is given by:

\vec{E} = \frac{Q}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

\vec{E} = \frac{71\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}

\vec{E} = 708.03 N/C

Now,

Electric field at the mid-point due to charge Q' is given by:

\vec{E'} = \frac{Q'}{4\pi\epsilon_{o}(\frac{d}{2})^{2}}

\vec{E'} = \frac{42\times 10^{- 9}}{4\pi\8.85\times 10^{- 12}(\frac{1.9}{2})^{2}}

\vec{E'} = 418.84 N/C

Now,

The net Electric field is given by:

\vec{E_{net}} = \vec{E} - \vec{E'}

\vec{E_{net}} = 708.03 - 418.84 = 289.19 N/C

5 0
3 years ago
When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal
Temka [501]

Ans the answer is 0.25J

Explanation

i guess

4 0
3 years ago
If the wavelength of a sound wave increases and the frequency of the sound wave does not change what happens to the speed of the
salantis [7]

If the wavelength of a sound wave increases and the frequency of the sound wave does not change, the speed of the wave will increase.

Ans: D

Explanation

The sound wave speed is given by E=fλ, where f indicates its frequency and λ indicates its wavelength.

From the equation, it is evident that the sound speed is proportional to both frequency and wavelength.

Here, as wavelength increases, wave speed increases provided there is no change in frequency.

3 0
3 years ago
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