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ioda
3 years ago
10

Which statement forms the basis of Faraday’s law of induction?

Physics
2 answers:
aleksley [76]3 years ago
8 0

Answer:

Did you ever get the answer?

Explanation:

Leviafan [203]3 years ago
3 0

Took one for the team, you're welcome. :)

Physics Unit 3 Lesson 3 : Magnetism and induction

1. 0.000 Wb

2. 6.0 T

3. 0 degrees

4. A changing magnetic flux establishes a current in a circuit.

5. 1.84 x 10^-3 Wb

6. While the ring is falling

7. The magnetic field must be changing.

8. 0.0 Wb

9. -5.80 x 10^-5 Wb

10. 60 degrees

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Answer:

Given =

Resistance = 20 ohm

Volt = 210 volts

Solution =

By Ohm's Law

R = V/I

I = V/R

I = 210/20

I = 11.5 ampere. Answer

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vector ????⃗ has a magnitude of 17.9 and its direction is 80∘ counter‑clockwise from the x- axis. what are the x- and y- compone
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We have vector (17.9*cos80^{0},17.9*sin80^{0})

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<h3>What is a vector?</h3>

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Volcano has both useful and harmful effects give reason​
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Read 2 more answers
In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point
Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ  X volume of the oil drop

volume of the oil drop (spherical) =  (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

=  (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0
2 years ago
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