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4 years ago

What's the difference between instantaneous and average velocity? How do you calculate both of them?

1 answer:

8 0

<span>Instantaneous velocity is calculated at a specific point and average velocity is calculated over a distance.
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Let's say I was taking a ride in my car to another city, and I drove for an hour. If the other city was 60 miles away, that means my average velocity would be 60 mph. But, during that trip, I got caught in a traffic jam, where at some point in time I was going 20 mph. That would be an example of instantaneous velocity.

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
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A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. what is the volume of the ball?

lesantik [10]

Density=mass/volume therefore volume=mass/density; 55g/11.4g/cm^3= 4.82cm^3

6 0

3 years ago

Read 2 more answers

The top of lake is frozen as atmospheric temperature is -10 degree Celsius the temperature of the bottom of the lake is most lik

hjlf

4°Celcius Water is densest at 4°C

4 0

4 years ago

A 1000-kg car is traveling east at 20\:m.s^{-1}20 m . s − 1 and a 1200-kg car is traveling west at 22\:m.s^{-1}\:22 m . s − 1. W

nydimaria [60]

Answer:

490,400 J

Explanation:

Mass of first car, m = 1000 kg

Mass of second car, M = 1200 kg

velocity of first car, u = 20 m/s east

velocity of second car, U = 22 m/s west

The formula for the kinetic energy is

$k = \frac{1}{2}mv^{2}$

where, m is the body and v be the velocity of the body.

Total kinetic energy is given by

$k = \frac{1}{2}mu^{2}+\frac{1}{2}MU^{2}$

$k = \frac{1}{2}\times1000\times20^{2}+\frac{1}{2}\times1200\times22^{2}$

$k = 200000 + 290400$

k = 490,400 J

Thus, the total kinetic energy of the system is 490,400 J.

3 0

3 years ago

Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. De

lyudmila [28]

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

T² = (4π² / G M) r³

When applying this equation to our case, the planet with a greater orbit must have a greater period.

Consequently Dean must have a period greater than San which has the smallest orbit

The correct answer is Dean has a period greater than San

3 0

3 years ago

1 point

Yuliya22 [10]

PE= 3kg x 10N/kg x 10m
= 300J

8 0

3 years ago