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4vir4ik [10]
3 years ago
15

do constructive inference occur when the compression of one wave meets up with the compression of a second wave

Physics
1 answer:
Ugo [173]3 years ago
6 0

Answer:

Yes

Explanation:

There are two types of interference possible when two waves meet at the same point:

- Constructive interference: this occurs when the two waves meet in phase, i.e. the crest (or the compression, in case of a longitudinale wave) meets with the crest (compression) of the other wave. In such a case, the amplitude of the resultant wave is twice that of the original wave.

- Destructive interferece: this occurs when the two waves meet in anti-phase, i.e. the crest (or the compression, in case of a longitudinal wave) meets with the trough (rarefaction) of the other wave. In this case, the amplitude of the resultant wave is zero, since the amplitudes of the two waves cancel out.

In this problem, we have a situation where the compression of one wave meets with the compression of the second wave, so we have constructive interference.

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Two negative charges that are both -3.0 C push each other apart with a force of 19.2 N. How far apart are the two charges ?
fgiga [73]
The Coulomb's force acting between two charges is
F=k_e  \frac{q_1 q_2}{r^2}
where k_e = 8.99 \cdot 10^9 N m^{-2}C^{-2} is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.

Using q_1 = q_2 = -3 C, we can find the distance between the two charges when the force is F=19.2 N:
r=  \sqrt{k_e  \frac{q_1 q_2}{F} }=  \sqrt{ 8.99\cdot 10^9 \frac{(-3.0C)^2}{19.2 N} }=6.5 \cdot 10^4 m = 65 km
5 0
3 years ago
When fossil fuels are burnt, what 2 gases are given off?
Mkey [24]
Salutations!

When fossil fuels are burnt, what 2 gases are given off?

When fossil fuels are burnt, the following are one of the two gases when they are given off:

→ Carbon dioxide: Carbon dioxide is a green house gas, and plays a major role in the global warming.

→ Carbon Monoxide: Carbon monoxide is a gas that is dangerous to human beings when released.

Hope I helped (:

Have a great day!
6 0
3 years ago
what nuclear fission and nuclear fusion have in common? A. They’re both used in power plants B. they have less mass than their r
arsen [322]

A. They’re both used in power plants . . . No.  

Nuclear fission is used in <u>all</u> nuclear power plants.  Fusion isn't used in <u>any</u> power plants yet, because we can't control it safely enough yet.  The only thing we can use nuclear fusion for is still bombs.

B. they have less mass than their reactants . . . No.  

Fission involves breaking atoms into pieces. Its products have less mass than its raw materials.  Fusion involves sticking atoms together to make new ones.  Its products have more mass than its raw materials.  Whatever the incomplete statement ' B ' is trying to say, it's not true of both processes.

<em>B. ==> </em> If you try really hard, this statement <em>(B)</em> can be undertood as true.  The TOTAL MASS after both a fission reaction and a fusion reaction is less than the total mass of whatever was fissled or fuzled.  In both cases, the missing mass is accounted for by the energy that was radiated from the site of the nuclear reaction.

But the statement in ' B ' is very poorly written.  When you read it, you don't know what 'they' refers to.  

C. they start with the same reactants . . . No.  

Man-made fission starts with the heaviest atoms ... Uranium and Plutonium.  Man-made fusion starts with the lightest atoms ... Hydrogen.

D. their products have more mass than their reactants ... No.

Fission breaks heavy atoms and makes lighter ones.  Fusion glues light atoms and makes heavier ones.

Gee whiz !  <em>None of the choices is correct. </em>

7 0
3 years ago
Read 2 more answers
If R is the total resistance of three resistors, connected in parallel, with resistances R1, R2, R3, then 1 R = 1 R1 + 1 R2 + 1
rjkz [21]

Answer:

maximum error is 0.03333

Explanation:

given data

R1 = 100 Ω,

R2 = 25 Ω,

R3 = 10 Ω

1/ R = 1/ R1 + 1/ R2 + 1 /R3

possible error = 0.5%

to find out

maximum error

solution

we know

1/ R = 1/ R1 + 1/ R2 + 1 /R3

put all value R1, R2 and R3

1/ R = 1/ 100 + 1/ 25 + 1 /10

R = 20/3

now take derivative  

dR/dR(i) = R²/R(i)² for i = 1, 2, 3

we have given error 0.005

so dR(i) = 0.005×R(i)  for the i = 1,2,3

so the equation will be

dR = dR/dR(1) ×dR(1) +dR/dR(2) ×dR(2) + dR/dR(3) ×dR(3)

dR = R²/R²(1) ×dR(1) + R²/R²(2) ×dR(2) +  R²/R²(3) ×dR(3)

put the value dR(1) and dR(2) and dR(3) and R

dR =  (20/3)²/R²(1) ×0.005×R(1) +  (20/3)²/R²(2) ×0.005×R(2) +   (20/3)²/R²(3) ×0.005×R(3)

dR =  (20/3)²/R(1) ×0.005 +  (20/3)²/R(2) ×0.005 +   (20/3)²/R(3) ×0.005

dR =  (20/3)²/100 ×0.005 +  (20/3)²/20 ×0.005 +   (20/3)²/10 ×0.005

dR =  (20/3)² ( 0.005/100 + 0.005/25 + 0.005/10)

dR = 0.033333

maximum error is 0.03333

8 0
3 years ago
Mercury in a container has a volume of 200cm and a density of 13.6 g/cm find the mass of the mercury
Sliva [168]
2.72 kilograms or 2720 grams.
7 0
3 years ago
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