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slamgirl [31]
3 years ago
9

If you have a 2700 gram sample of C-14 and 12 half-lives have passed how much of your original sample

Chemistry
1 answer:
givi [52]3 years ago
8 0

Answer:

A ( t )=0.659 gram of C-14

Explanation:

Mathematically exponential decay can be expressed as

where

A ( t )   - the amount left after t years;

A 0  - the initial quantity of the substance that will undergo decay;

t 1/2  - the half-life of the decaying quantity.

Calculation:

Given that

A 0  =2700 gram sample of C-14

t=time=12 times of half life of C-14

Required data:

A ( t )=?

Putting value in the attached equation we get

A ( t )=0.659 gram of C-14

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Answer:This particular enzyme promotes the breakdown of starches into simpler sugars which can be absorbed by the body. Salivary amylase, like most other enzymes, is a protein. ... Consequentlysalivary amylase does not function once it enters the stomach.

Explanation:

6 0
3 years ago
40. What is the mass of 3 moles of H 2 O
Leya [2.2K]

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O  = 3 moles

Unknown:

mass of water  = ?

Solution:

To solve this problem, we use the expression below:

         mass  = number of moles x molar mass

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3 0
3 years ago
A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature
Doss [256]

Answer:

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Explanation:

5 0
3 years ago
slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.
pishuonlain [190]

<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> The equation is _{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> The equation is _{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

<u>Explanation:</u>

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

<u>For A:</u> Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

6 0
3 years ago
The ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol of ch4 reacts, what is the total amount
Leni [432]
<span>CH4 + 4 Cl2 → CCl4 + 4 HCl (4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4 (4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl CCl4 + 2 HF → CCl2F2 + 2 HCl (2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl 11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>
8 0
3 years ago
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