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3 years ago

If you have a 2700 gram sample of C-14 and 12 half-lives have passed how much of your original sample

Chemistry

1 answer:

givi [52]3 years ago

8 0

Answer:

A ( t )=0.659 gram of C-14

Explanation:

Mathematically exponential decay can be expressed as

where

A ( t ) - the amount left after t years;

A 0 - the initial quantity of the substance that will undergo decay;

t 1/2 - the half-life of the decaying quantity.

Calculation:

Given that

A 0 =2700 gram sample of C-14

t=time=12 times of half life of C-14

Required data:

A ( t )=?

Putting value in the attached equation we get

A ( t )=0.659 gram of C-14

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When the u-235 nucleus is struck with a neutron, the zn-72 and sm-160 nuclei are produced, along with some neutrons. How many ne

Oxana [17]

4 neutrons that are produced along with the Zn and sm. The complete final equation is: ²³⁵U + ¹n → $\;^{72}Zn+\;^{160}sm$ + 4 n

<h3>What atomic mass?</h3>

Atomic mass, the quantity of matter contained in an atom of an element.

1) In the left side of the transmutation equation appears:

²³⁵U + ¹n →

Deleting the atomic number (subscript to the left) because the question does not show them as it is focused on a number of neutrons.

2) The right side of the transmutation equation has:

→ $\;^{72}Zn+\;^{160}sm$ +?

3) The total mass number of the left side is 235 + 1 = 236

4) The total mass number of Zn and sm on the right side is 160 + 72 = 232

5) Then, you are lacking 236 - 232 = 4 unit masses on the right side which are the 4 neutrons that are produced along with the Zn and sm.

The complete final equation is:

²³⁵U + ¹n → $\;^{72}Zn+\;^{160}sm$ + 4 n

Learn more about the atomic mass here:

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8 0

2 years ago

A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo

julsineya [31]

The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
Structure of Intermediate is shown both in 2-D and 3-D (below attached).

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

4 0

3 years ago

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n

Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ= $\frac{-2.18*10^{-18} J}{n^{2} }$

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE= $-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )$

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ= $\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s }{9.1760*10^{-20} J }$

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0

4 years ago

What is the percentage composition of each element in hydrogen peroxide, H2O2?

Degger [83]

Answer:

The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).

Explanation:

Step 1: Data given

Molar mass of H = 1.0 g/mol

Molar mass of O = 16 g/mol

Molar mass of H2O2 = 2*1.0 + 2*16 = 34.0 g/mol

Step 2: Calculate % hydrogen

% Hydrogen = ((2*1.0) / 34.0) * 100 %

% hydrogen = 5.88 %

Step 3: Calculate % oxygen

% Oxygen = ((2*16)/34)

% oxygen = 94.12 %

We can control this by the following equation

100 % - 5.88 % = 94.12 %

The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).

8 0

3 years ago

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What is missing from the solubility graph shown on the right? A graph with temperature in degrees Celsius ranging from 0 to 100

AVprozaik [17]

Answer:

graph title, label for the y axis, and legend explaining the orange and blue colors

Explanation:

8 0

3 years ago

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