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slamgirl [31]
3 years ago
9

If you have a 2700 gram sample of C-14 and 12 half-lives have passed how much of your original sample

Chemistry
1 answer:
givi [52]3 years ago
8 0

Answer:

A ( t )=0.659 gram of C-14

Explanation:

Mathematically exponential decay can be expressed as

where

A ( t )   - the amount left after t years;

A 0  - the initial quantity of the substance that will undergo decay;

t 1/2  - the half-life of the decaying quantity.

Calculation:

Given that

A 0  =2700 gram sample of C-14

t=time=12 times of half life of C-14

Required data:

A ( t )=?

Putting value in the attached equation we get

A ( t )=0.659 gram of C-14

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lutik1710 [3]
Correct answer is <span>X = ΔH

Reason:
1) The graph of enthalpy Vs reaction coordinate  suggest the reaction is endothermic in nature. For endothermic reaction, energy if product is more than that of reactant. Hence,  option 1 i.e. </span><span>X = -ΔH cannot be correct.
2) Since the reaction is endothermic in nature, </span>energy if product is more than that of reactant. Hence,  option 2 i.e. X = ΔH is correct.
3) Activation energy is energy difference between Reactant (A) and transition state (B). However, as per option C, activation energy (A.E.) is energy difference between product (C) and transition state (B), which is incorrect. 
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3 years ago
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<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

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W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


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3 years ago
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anyanavicka [17]

Explanation:

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