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3 years ago

What is the result of 2.58×0.12, including correct significant figures? Select the correct answer below: 0.3096 0.31 0.310 0.3

Chemistry

2 answers:

Masteriza [31]3 years ago

7 0

Answer:

wrnognioegnewoiegoi

Explanation:

Pavel [41]3 years ago

5 0

Answer:

The answer would depend on the required significant number.

Explanation:

0.3096 is the complete answer

0.31 is the answer when the hundredths place is asked

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Predict the products that will be formed by the reaction below. Al(s)+Na2SO4(s)—>

Ostrovityanka [42]

Answer:

Al₂(SO₄)₃ and Na

Explanation:

Al has a charge of +3, Na has a charge of +1 and SO₄ has a charge of -2. Since cations and anions will bond we know that Al will bond with SO₄ leaving Na by itself (since this is a single replacement reaction). When Al bonds with SO₄ it makes aluminum sulfate which is Al₂(SO₄)₃ and Na will be left by itself.

3 0

3 years ago

Which substance has Hf defined as 0 kJ/mol? H2O (s) Ne (l) O2 (g) CO2 (g)

vlabodo [156]

Answer:

O₂ (g).

Explanation:

All elements that found in nature has heat of formation (Hf) equal 0 J/mol.

So, the substance that has heat of formation (Hf) equal 0 J/mol is O₂ (g).

H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).

Although, Ne (g) is found in nature and has no Hf, the liquification to form Ne (l) has heat of formation (Hf).

CO₂ (g) is formed from the reaction between carbon and oxygen and so has heat of formation (Hf).

8 0

3 years ago

Read 2 more answers

A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm

VARVARA [1.3K]

<u>Answer:</u> The nuclear equations for the given process is written below.

<u>Explanation:</u>

The chemical equation for the bombardment of neutron to U-238 isotope follows:

$_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}$

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The chemical equation for the first beta decay process of $_{92}^{239}\textrm{U}$ follows:

$_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta$

The chemical equation for the second beta decay process of $_{93}^{239}\textrm{Np}$ follows:

$_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta$

Hence, the nuclear equations for the given process is written above.

6 0

3 years ago

A sample of carbon dioxide gas occupies a volume of 250 mL at 25c what volume will it occupy at 95c

anzhelika [568]

Considering the Charles's law, the sample of carbon dioxide gas will occupy 308.72 mL.

<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

Mathematically, Charles's law states that the ratio between volume and temperature will always have the same value:

$\frac{V}{T} =k$

Considering an initial state 1 and a final state 2, it is fulfilled:

$\frac{V1}{T1} =\frac{V2}{T2}$

<h3>Final volume in this case</h3>

In this case, you know:

V1= 250 mL
T1= 25 C= 298 K (being 0 C=273 K)
V2= ?
T2= 95 C= 368 K

Replacing in Charles's law:

$\frac{250 mL}{298 K} =\frac{V2}{368 K}$

Solving:

$V2=368 K\frac{250 mL}{298 K}$

Finally, the sample of carbon dioxide gas will occupy 308.72 mL.

Learn more about Charles's law:

brainly.com/question/4147359

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6 0

2 years ago

Help pleaseee

marissa [1.9K]

Answer:

In order to find the molecular formula from an empirical formula you must find the ratio of their molecular masses.

We know that the molecular mass of the molecule is 70

gmol-1

. We can calculate the molar mass of

CH2

from the periodic table:

C=12.01

gmol−1

H=1.01

gmol−1

CH2 =14.03

gmol−1

Hence we can find the ratio:

14.03

≈

0.2

6 0

3 years ago