20 meters per second. I use the formula V^2=V0^2 + 2*a*d. a is acceleration and d is distance.
Answer:
Minimum speed will be equal to 2.213 m/sec
Explanation:
We have given radius of the r = 2 m
Coefficient of friction 
At minimum speed frictional force will be equal to centripetal force
So 
So the minimum speed will be equal to 2.213 m/sec
The string that will break first depends on the weight of the block or bar subjected to such string.
According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.
F= kx
where;
- <em>F is the force applied to the object = weight of the object</em>
For given two identical strings, the string that will break first depends on the mass of the bar and the block.
- If the bar is heavier than the block, then the string subjected to the bar will break first.
- On the other hand, if the block is heavier than the bar, then the string subjected to the block will break first.
Thus, the string that will break first depends on the weight of the block or bar subjected to such string.
Learn more here:brainly.com/question/4404276
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