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2 years ago

Please answer ASAP!!!

Chemistry

2 answers:

Nookie1986 [14]2 years ago

6 0

Answer:

A. Conducting a drug experiment which will harm lab rats

Explanation:

Karolina [17]2 years ago

4 0

A. Conducting a drug experiment which will harm lab rats

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In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)

lyudmila [28]

Answer : The mass of $NaBr$ is, 295.323 grams

Solution :

First we have to calculate the moles of $NaNO_3$ .

$\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles$

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

$Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)$

From the balanced reaction we conclude that

As, 2 moles of $NaNO_3$ react with 2 moles of $NaBr$

So, 2.87 moles of $NaNO_3$ react with 2.87 moles of $NaBr$

Now we have to calculate the mass of NaBr.

$\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr$

$\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g$

Therefore, the mass mass of $NaBr$ is, 295.323 grams

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2 years ago

How to do lewis dot structure of nh3conh3

wlad13 [49]

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2 years ago

Name the process that changes matter into one or more new substances

Brums [2.3K]

Chemical change or process

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3 years ago

If not managed properly, aquaculture can

Damm [24]

C. pollute water and damage aquatic ecosystems

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3 years ago

A 21.0 kg child is running at a velocity of 2.50 m/s. The child is carrying a 2.25 kg gallon of milk. What is the momentum of th

KIM [24]

Answer: The momentum of the child and milk together is 58.125 kg.m/s

Explanation:

Momentum is defined as the product of object's mass and velocity.

Mathematically,

$p=mv$

where, p = momentum

m = mass of the object

v = velocity of the object

In the given question, we are given that a child of mass 21.0 kg is carrying a gallon of milk having mass 2.25 kg and running with a velocity of 2.5 m/s. Hence, the momentum by both milk and child will be:

$p=(m_{child}+m_{milk})v$ ....(1)

Given:

$m_{child}=21.0kg\\m_{milk}=2.25kg\\v=2.5m/s\\p=?kg.m/s$

Putting values in equation 1, we get:

$p=(21+2.25)kg\times 2.5m/s=58.125kg.m/s$

Hence, the momentum of the child and milk together is 58.125 kg.m/s

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3 years ago